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natima [27]
2 years ago
10

Could you please show the work for both of them?​

Mathematics
1 answer:
lesantik [10]2 years ago
3 0
7. y=-3/2x+8 (3rd answer choice)

substitute
-4=-3/2(8)+b
-4=-24/2 +b
-4=-12+b
+12 both sides
8=b

so equation would be...

y=-3/2x+8 (3rd answer choice)




8. y=-5x-17 (2nd answer choice)

substitute
-2=-5(-3)+b
-2=15+b
-15 both sides
-17=b

so the equation would be...

y=-5x-17 (2nd answer choice)


check your work by substituting each (x,y) value into the final equations if you want. hope this helps :))
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What is the domain of the relation graphed below?
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Answer:

domain: (-4,4)

Step-by-step explanation:

i'm not sure if it has brackets because it doesn't have point that are on x-intervals -4 and 4

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Drag statements and reasons to each row to show why the slope of the line between P and Q is the same as the slope between Q and
Delvig [45]

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Row One: Statement: 3/2=slope Reason: Definition of Slope

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5 0
3 years ago
Read 2 more answers
Please help me with this.
OLga [1]

Swapping rows alters the sign of the determinant:

\begin{vmatrix} x & y & z \\ -8 & 2 & -12 \\ u & v & w \end{vmatrix} = - \begin{vmatrix} x & y & z \\ u & v & w \\ -8 & 2 & -12 \end{vmatrix}

Multiplying a single row by a scalar scales the determinant by the same amount:

\begin{vmatrix} x & y & z \\ u & v & w \\ -8 & 2 & -12 \end{vmatrix} = -2 \begin{vmatrix} x & y & z \\ u & v & w \\ 4 & -1 & 6 \end{vmatrix}

Then

\begin{vmatrix} x & y & z \\ -8 & 2 & -12 \\ u & v & w \end{vmatrix} = -(-2) \begin{vmatrix} x & y & z \\ u & v & w \\ 4 & -1 & 6 \end{vmatrix} = 2\times(-6) = \boxed{-12}

8 0
2 years ago
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