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3 years ago

3. A regular hexagon has six equilateral triangles with a common

Mathematics

1 answer:

hichkok12 [17]3 years ago

8 0

Answer:

if the height of the triangle is 8 in, its side is 9.2379, and this side is also the side of the hexagon, so the perimeter is 6*9.2379 = 55.43 in

Step-by-step explanation:

As the hexagon is regular, each of those triangles will also be regular.

So if the height of one triangle is 8 inches, we can find the side of the triangle with the height formula of a regular triangle:

height = side * sqrt(3)/2

8 = side * 0.866

side = 8/0.866 = 9.2379

The side of the triangle will also be the side of the hexagon. So the perimeter of the hexagon will be:

P = 6 * 9.2379 = 55.43 inches

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Step-by-step explanation:

Given coordinate of vertex is $(-\frac{1}{2},2.3)$ and the parabola passes through the point $(5,2\frac{3}{4})$

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Plugging these value in equation we get,

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$2.75=a(5-(-0.5))^2+2.3\\\\2.75=a(5+(0.5))^2+2.3\\\\2.75=a(5.5)^2+2.3\\\\2.75=a\times30.25+2.3\\\\2.75-2.3=a\times30.25\\\\0.45=a\times30.25\\\\\frac{0.45}{30.25}=a\\ \\a=0.0149$

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$y=0.0149(x+0.5)^2+2.3$ ≅ $y=0.015(x+0.5)^2+2.3$

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