Explanation:
Pair 1 is true if Jeff's monthly income is $600/20% = $3,000.
Pair 2 is true if Jeff's monthly income is $1200/10% = $12,000.
Both pairs can be true if Jeff's monthly income increased by a factor of 4 in the 20 years from 1990 to 2010.
Obviously, Jeff spent more on housing in 2010. (Fortunately for Jeff, that larger expenditure was a smaller fraction of his income.)
Answer:
Step-by-step explanation:
Answer:
y = -24 + -2x + 2x2
Step-by-step explanation:
Simplifying:
y = 2(x + 3)(x + -4)
reorder the terms:
y = 2(3 + x)(x + -4)
multiply (3 + x) * (-4 + x)
y = 2(3(-4 + x) + x(-4 + x))
y = 2((-4 * 3 + x * 3) + x(-4 + x))
y = 2((-12 + 3x) + x(-4 + x))
y = 2(-12 + 3x + (-4 * x + x * x))
y = 2(-12 + 3x + (-4x + x2))
Combine like terms 3x + -4x = -1x
y = 2(-12 + -1x + x2)
y = (-12 * 2 + -1x * 2 + x2 * 2)
y = (-24 + -2x + 2x2)
Solving:
y = -24 + -2x + 2x2
solving for variable 'y'
Move all terms containing y to the left, all other terms to the right.
Simplifying:
y = -24 + -2x + 2x2
Answer:
What is P(A), the probability that the first student is a girl? (3/4)
What is P(A), the probability that the first student is a girl? (3/4)What is P(B), the probability that the second student is a girl? (3/4)
What is P(A), the probability that the first student is a girl? (3/4)What is P(B), the probability that the second student is a girl? (3/4)What is P(A and B), the probability that the first student is a girl and the second student is a girl? (1/2)
The probability that the first student is a girl is (3/4), likewise for the 2nd 3rd and 4th it's still (3/4). The order you pick them doesn't matter.
However, once you're looking at P(A and B) then you're fixing the first position and saying if the first student is a girl what's the probability of the second student being a girl.
Answer:
2 books
Step-by-step explanation:
10 + 5x = 16 + 2x
- 2x - 2x
10 + 3x = 16
-10 -10
3x = 6
/3 /3
<u>x = 2</u>
