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IRISSAK [1]
3 years ago
6

PLEASEEEEEEEEEEEEE HELPPPPPPPPPPPPPPPPPPPPPPP

Mathematics
1 answer:
viva [34]3 years ago
7 0
A)obtuse
B)acute
C)obtuse
D)right
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Wich algebraic expression represents ”forty times a number”?<br><br> 40+n<br> 40n<br> n-40<br> 40/n
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The answer to the problem is 40n
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I WILL GIVE BRAINLIEST IF YOU ANSWER!!!
harkovskaia [24]

Answer:

Leena consumed 1,500 calories at dinner

Step-by-step explanation:

The reason the answer is Leena consumed 1,500 calories at dinner is because she consumes 2/3 of her daily calories at dinner.

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3 years ago
After the mill in a small town closed down in 1970, the population of that town started decreasing according to the law of expon
wlad13 [49]

Answer:

P_o = \frac{143000}{e^{-20*0.01303024661}}=110193.69

And we can round this to the nearest up integer and we got 110194.  

Step-by-step explanation:

The natural growth and decay model is given by:

\frac{dP}{dt}=kP   (1)

Where P represent the population and t the time in years since 1970.

If we integrate both sides from equation (1) we got:

\int \frac{dP}{P} =\int kdt

ln|P| =kt +c

And if we apply exponentials on both sides we got:

P= e^{kt} e^k

And we can assume e^k = P_o

And we have this model:

P(t) = P_o e^{kt}

And for this case we want to find P_o

By 1990 we have t=20 years since 1970 and we have this equation:

143000 = P_o e^{20k}

And we can solve for P_o like this:

P_o = \frac{143000}{e^{20k}}   (1)

By 2019 we have 49 years since 1970 the equation is given by:

98000 = P_o e^{49k}   (2)

And replacing P_o from equation (1) we got:

98000=\frac{143000}{e^{20k}} e^{49k} =143000 e^{29k}  

We can divide both sides by 143000 we got:

\frac{98000}{143000} =0.685 = e^{29k}

And if we apply ln on both sides we got:

ln(0.685) = 29k

And then k =-0.01303024661[/tex]

And replacing into equation (1) we got:

P_o = \frac{143000}{e^{-20*0.01303024661}}=110193.69

And we can round this to the nearest up integer and we got 110194.  

7 0
3 years ago
100 POINTS!!!
Y_Kistochka [10]

Answer:

<h2><u><em>D. 12/4 and 3/1</em></u></h2>

Step-by-step explanation:

What two ratios can be written for the following illustration comparing oranges to bunches of bananas? (image of 12 oranges and 4 bananas) A. 12/4 and 1/3 B. 4/12 and 3/1 C. 3/3 and 1/1 D. 12/4 and 3/1

12 oranges and 4 bananas is

12/4

semplify

3/1

7 0
2 years ago
In a given rectangle, the longer sides are 7 units longer than the shorter sides. If we let the shorter sides be represented as
strojnjashka [21]

Answer: D because the two longer sides are 7 unites longer, meaning you need to add 14 (7x2) to the final product

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