Answer:
Wonka bars=3 and Everlasting Gobstoppers=24
Step-by-step explanation:
let the wonka bars be X
and everlasting gobstoppers be Y
the objective is to
maximize 1.3x+3.2y=P
subject to constraints
natural sugar
4x+2y=60------1
sucrose
x+3y=75---------2
x>0, y>0
solving 1 and 2 simultaneously we have
4x+2y=60----1
x+3y=75------2
multiply equation 2 by 4 and equation 1 by 1 to eliminate x we have
4x+2y=60
4x+12y=300
-0-10y=-240
10y=240
y=240/10
y=24
put y=24 in equation 2 we have'
x+3y=75
x+3(24)=75
x+72=75
x=75-72
x=3
put x=3 and y=24 in the objective function we have
maximize 1.3x+3.2y=P
1.3(3)+3.2(24)=P
3.9+76.8=P
80.7=P
P=$80.9
I know none of these are actually the answer but odysseyware gave me credit for
(4,2)
-15x=-4x
We know that adding zero wouldn’t change the value
-15x=-4x+0
Now we can add 4x (since that’s the opposite of the negative sign) to the other side
-11x=0
0 divided by 11 is 0
x=0
Answer:
do i supposed to add them all together
Step-by-step explanation:
Answer:
q=3
Step-by-step explanation:
