A.) For the Junior Varsity Team, mean would be the appropriate measure of center since the data is <span>symmetric or well-proportioned while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.
b.) For the Varsity Team, the median would be the appropriate measure of the center since the data is skewed left and not evenly distributed so median could be used since it does not account for outliers while we use IQR or interquartile range in measuring the spread of data since IQR does not account for the data that is skewed. </span>
Given:
The expression is:
To find:
Part A: The expression using parentheses so that the expression equals 23.
Part B: The expression using parentheses so that the expression equals 3.
Solution:
Part A:
In option A,
[Using BODMAS]
In option B,
[Using BODMAS]
In option C,
In option D,
[Using BODMAS]
After the calculation, we have and .
Therefore, the correct options are B and D.
Part B: From part A, it is clear that
Therefore, the correct option is C.
You make a bar and you take 34 and shade 18. Count the squares not shaded.
Don't take my word on this. I may be wrong.
Answer:
250
Step-by-step explanation:
divide 1000 by 4 and you will get the unit rate
What’s the question your asking here ?
