Answer:
On average, cars enter the highway during the first half hour of rush hour at a rate 97 per minute.
Step-by-step explanation:
Given that, the rate R(t) at which cars enter the highway is given the formula

The average rate of car enter the highway during first half hour of rush hour is the average value of R(t) from t=0 to t=30.

![=[100(t-0.0001\frac{t^3}{3})]_0^{30}](https://tex.z-dn.net/?f=%3D%5B100%28t-0.0001%5Cfrac%7Bt%5E3%7D%7B3%7D%29%5D_0%5E%7B30%7D)
![=100[(30-0.0001\frac{30^3}{3})-(0-0.0001\frac{0^3}{3})]](https://tex.z-dn.net/?f=%3D100%5B%2830-0.0001%5Cfrac%7B30%5E3%7D%7B3%7D%29-%280-0.0001%5Cfrac%7B0%5E3%7D%7B3%7D%29%5D)
=2901
The average rate of car is 

=97
On average, cars enter the highway during the first half hour of rush hour at a rate 97 per minute.
#1
Area of base=1/2(2.8)(4.2)
Volume:
- Area of base×Height
- 5.88(7)
- 41.16in³
#2
Area of base
- 6×1/2(7)(6.1)
- 3(7)(6.1)
- 128.1cm²
Volume:-
Answer:
x = 12.6
Step-by-step explanation:
Sum of measure of all the arcs of a circle = 360°
m(arc CD) + m(arc CED) = 360°
Since, m(arc CED) = (20x)°
And m(arc CD) = (8x + 6)°
By substituting these measures in teh expression,
(20x)° + (8x + 6)° = 360°
(20x + 8x) + 6 = 360
28x = 360 - 6
28x = 354
x = 
x = 12.64
x = 12.6
Y = -3x + 6....the slope here is -3. A parallel line will have the same slope.
y = mx + b
slope(m) = -3
(-4,7)....x = -4 and y = 7
now we sub into the formula and find b, the y int
7 = -3(-4) + b
7 = 12 + b
7 - 12 = b
-5 = b
so ur parallel equation is : y = -3x - 5 <==