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yKpoI14uk [10]
2 years ago
13

The size of the tank a fish collector needs depends on how many fish he has. Which in the independent variable

Mathematics
1 answer:
Semenov [28]2 years ago
3 0

Answer:

Step-by-step explanation:

"<u><em>The size of the tank</em></u> a fish collector needs <u><em>depends</em></u> on <em>how many fish he has</em>."

Dependent variable is the size of the tank.

<em>Independent variable</em> is how many fish a fish collector has.

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What's 789,091 rounded to the hundred thousands
Elena-2011 [213]
We need to round the number to the nearest hundred throusands.
this means that we will check the number after the poaition of the hundred thousands, if it is 5 or more,then we will add one otherwise we will ignore it and add zeros.
based on this, the number in the position next to the hundred thousands is 8 which mean that we will add one to the hundred thousands positions while all others will become zero.
Therefore,
789,091 to the nearest hundred thousands is 800,000
7 0
3 years ago
Read 2 more answers
A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang
laiz [17]

<u>Answer-</u>

a. Probability that  three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

<u>Solution-</u>

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

\binom{19}{3} = \frac{19!}{3!16!} = 969

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

\binom{33}{6} = \frac{33!}{6!27!} =1107568

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

\binom{52}{9} = \frac{52!}{9!43!} = 3679075400

∴P(3 white candies) = \frac{1073233392}{3679075400} =0.29



Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}

=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})

=(969)(45)(7)(5)(15)=22892625

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

\binom{52}{9}=\frac{52!}{9!43!} =3679075400

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

\frac{22892625}{3679075400} = 0.006


6 0
3 years ago
Which numbers is 90 divisible by
SIZIF [17.4K]

1 x 90

2 x 35

3 x 30

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9 x 10

7 0
3 years ago
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PLEASE RESPOND!!!
solniwko [45]

Did you ever get the answer

5 0
2 years ago
Only 18 people are allowed on a ride at the same time. There are 157 people waiting in line. How many groups of riders will ther
IrinaK [193]

Answer:

Step-by-step explanation:

Divide 157 by 8 to see how many groups there are.

157/18=8r13. So you can round up to 9 groups of riders as there is a max of 18 at a time.

7 0
2 years ago
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