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Pani-rosa [81]
3 years ago
5

What are soulutions to x^2 - 2x - 24 = 0 who is brainliest

Mathematics
2 answers:
ratelena [41]3 years ago
8 0

Answer:

(x - 6)(x + 4) = 0.

Step-by-step explanation:

With your case of x2 - 2x - 24, we have b1+b2 = -2 and b1b2 = 1*(-24) = -24. So the equation x2 - 2x - 24 = 0 becomes (x - 6)(x + 4) = 0.

11111nata11111 [884]3 years ago
6 0

Answer:

Solve using the quadratic formula.

x = 6, −4

Step-by-step explanation:

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What is the basic ratio for 25:40
Rashid [163]

The basic ratio of 25:40 would be 5:8.

Since 25:40 is equivalent to the fraction 25/40, you would simplify.


25 (divided by) 5 = 5 


40 (divided by) 5 = 8 


So, the answer is 5:8.

6 0
3 years ago
Alicia drew a pentagon with equal side lengths and equal angles. Then she added red lines of symmetry to her drawing. How many l
son4ous [18]
A pentagon is a regular polygon with five equal sides and five equal interior angles. Also, it has five vertices. To draw the line that would divide the figure equally into two, we simply have to draw a line from one vertex and then extend the line to the opposite side.

Since, there are five vertices then, she will be able to draw five. 

<em>Answer: 5</em>
8 0
3 years ago
A baseball player had a batting average of 0.334 for the season. Write this numbwr in expanded form​
Readme [11.4K]

Answer:

0.300 + 0.030 + 0.004

or

0.100 x 3  +  0.01 x 3  +  0.001 x 4

8 0
2 years ago
Is it true that the order when dividing three real numbers does not effect the answer?
Diano4ka-milaya [45]

When dividing three real numbers the order can effect the answer.

Example:

8:4:2

1. 8:4:2=(8:4):2=2:2=1;

2. 8:4:2=8:(4:2)=8:2=4.

As you can see the results are different.

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7 0
3 years ago
Read 2 more answers
Which condition is sufficient to show that quadrilateral DEFG is a parallelogram?
Whitepunk [10]

Answer:

Option D

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Step-by-step explanation:

To use the supplementary property to identify a parallelogram. The condition must be that that the same-side interior angles (consecutive angles) are supplementary.

Thus for parallelogram DEFG

        D --------------------E

         /                      /

     G---------------------F

Thus, we have it that the condition that is most sufficient to show that quadrilateral DEFG is a parallelogram is

∠GDE is supplementary to both ∠DEF and ∠FGD

4 0
3 years ago
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