Answer:
AD = 7
Step-by-step explanation:
Given that the two triangles are similar by the SSS (side side side) postulate, the triangles share the same ratios when it comes to their sides.
We know the values for lines DB, EB and CB, therefore we can solve for AB, and subtract DB to find AD
We can solve the problem by solving for x:
Cross multiply.
Simplify.
Subtract the value of DB to find AD.
Study all notes, reread the chapters again. Have someone ask questions on the chapters page by page. This always has worked for me. Plus try to do this again the night before the test. You will be surprised how much you can remember by doing it again the night before the test. Hope this helps.
Answer:
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The answer is D because 42 / 6 = 7 and the power ( ^X) can cancel out each other
A) area of square = base*height/////Triangle= 0.5*base*height
=(a^1/3*b^3/4)*(a^2/3*b^1/2)+(1/2*a^1/3*b^3/4*a^2/3*b^1/4)
=(a^1*b^5/4)+(1/2*a^1*b^1)
=(a*b^5/4)+(1/2*a*b)
B) a^2+b^2=c^2 (pythagorean theorem)
((27^2/3)*(16^1/4))^2 + (27^1/3)*(16^3/4)
(9*2=(18^2))=324 + (3*8= 24^2)= 576
324+576= 900
(900)^1/2= 30
hypotenuse= 30
C)( a^2/3*b^1/2)= 36*2(two sides)= 72
(a^1/3b^3/4)=24
(a^2/3*b^1/4)= 18
72+24+18+30(hypotenuse)= 144=perimeter
