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sweet-ann [11.9K]
3 years ago
5

Please help, I’m running out of time. Please.

Mathematics
1 answer:
Georgia [21]3 years ago
6 0

Answer:

which standard questions is it

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What is the slope of the line passing through the points (6, 7) and (1, 5) ?
rodikova [14]

2/5 as

5 - 7/1 - 6 = -2/-5. Dividing a negative number by a negative gives you a positive so 2/5.

6 0
4 years ago
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Geologist has collected 10 specimens of basaltic rock and 10th specimens of granite. The geologist instructs a laboratory assist
olya-2409 [2.1K]

Answer:

p(5)=0.00136

(a) p(x)=\frac{(10Cx)*((10)C(15-x))}{20C10}

(b)p(10)+p(5)=0.00272

(c)p(7)+p(8)=0.0584

Step-by-step explanation:

If we have N elements with k elements that we consider success and N-k elements that we consider fail, and we take a sample of n elements, the probability that there are x successes in the sample follows a hypergeometric distribution, so it is calculated as:

p(x)=\frac{(kCx)*((N-k)C(n-x))}{NCn}

In this case, N is equal to 20, k is equal to 10 specimens of granite rock, N-k is equal to 10 specimens of basaltic rock and n is 15. So, the probability that there are x specimens of granite rock in the sample or the pmf of the number of granite specimens selected for analysis is:

p(x)=\frac{(10Cx)*((10)C(15-x))}{20C10}

Now, the probability of getting exactly 5 granite specimens selected for analysis is:

p(5)=\frac{(10C5)*((10)C(15-5))}{20C10}=0.00136

On the other hand, the probability that all specimens of one of the two types of rock are selected  for analysis is the probability to select 10 granite specimens or 10 basaltic specimens. Where the probability to take 10 basaltic specimens is equal to the probability to take 5 granite specimens.

Then, the probability that all specimens of one of the two types of rock are selected  for analysis is:

p(10)+p(5)=\frac{(10C10)*((10)C(15-10))}{20C10}+\frac{(10C5)*((10)C(15-5))}{20C10}\\p(10)+p(5)=0.00136+0.00136=0.00272

For the hypergeometric distribution, the mean E(x) and standard deviation S(x) are:

E(x)=\frac{nk}{N}=\frac{15*10}{20}=7.5\\S(x)=\sqrt{\frac{nk}{N}*(1-\frac{k}{N})*(\frac{N-n}{N-1})}\\S(x)=\sqrt{\frac{15*10}{20}*(1-\frac{10}{20})*(\frac{20-15}{20-1})}=0.9934

Then, the number of granite specimens within 1 standard deviation of its mean value is:

  E(x) - S(x) ≤ mean ≤ E(x) + S(x)

7.5-0.9934 ≤ mean ≤ 7.5+0.9934

     6.5066 ≤ mean ≤ 8.4934

               7 ≤ mean ≤ 8

Finally, the probability that the number of granite specimens selected for analysis is  within 1 standard deviation of its mean value is:

p(7)+p(8)=\frac{(10C7)*((10)C(15-7))}{20C10}+\frac{(10C8)*((10)C(15-8))}{20C10}\\p(10)+p(5)=0.0292+0.0292=0.0584

8 0
4 years ago
Sara bought a 16-ounce jar of strawberry jam for $ 3.20. what is the unit price?
allochka39001 [22]
The unit price would be $0.20 because when you divide $3.20 by 16, that is what you would get. The equation would be
$3.20/ 16 oz. = $0.20
8 0
4 years ago
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Find the measure of ∠EGC. Circle A with chords EF and CD that intersect at point G, the measure of arc EC is 50 degrees, the mea
miv72 [106K]

Answer:

m∠EGC=70°

Step-by-step explanation:

we know that

The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite

so

m∠EGC=(1/2)[arc EC+arc DF]

<u><em>Find the value of x</em></u>

we have

m∠EGC=(7x+7)°

arc EC=50°

arc DF=10x°

substitute and solve for x

(7x+7)°=(1/2)[50°+10x°]

14x+14=50+10x

14x-10x=50-14

4x=36

x=9

<u><em>Find the measure of angle EGC</em></u>

m∠EGC=(7x+7)°

substitute the value of x

m∠EGC=(7(9)+7)°=70°

8 0
4 years ago
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Write a complete two-column proof for the following information given
rosijanka [135]

   <u>Statement </u>                  <u>Reason</u>        

1. AB = x + 16                 1. Given

  BC = 4x + 11

   AC = 77

2. AB + BC = AC             2. Segment Addition Postulate

3. x + 16 + 4x + 11 = 77     3. Substitution Property

4. 5x + 27 = 77                 4. Simplification <em>(added like terms)</em>

5. 5x = 50                         5. Subtraction Property of Equality

6. x = 10                             6. Division Property of Equality

7. AB = 10 + 16                   7. Substitution Property

8. AB = 26                          8. Simplification <em>(added like terms)</em>

5 0
4 years ago
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