<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>8</em><em>/</em><em>7</em>
<em>pl</em><em>ease</em><em> see</em><em> the</em><em> attached</em><em> picture</em><em> for</em><em> full</em><em> solution</em>
<em>Hope </em><em>it</em><em> helps</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>
The number of solutions of a quadratic equation
ax^2+bx+c=0
Depends on its discriminant
/Delta=b^2-4ac
If /Delta>0 there are two distinct solutions
If /Delta=0 there are two coincident solutions
If /Delta<0 there are no solutions.
We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:
The number of solutions of a quadratic equation
Depends on its discriminant
If there are two distinct solutions
If there are two coincident solutions
If there are no solutions.
We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:
b^2-4ac=9+28t>0\iff t>-\dfrac[9][28]
Elimination method is my favorite way to solve 2 equations like this written in standard form! First I'm going to rewrite the equations and mark numbers to make this explanation more clear.
2x-3y=251️⃣
5x+3y=102️⃣
Looking at these 2 equations we can see that there is a +3 and a -3. This could be eliminated by adding the 2 equations together! *Remember what is on the left side adds with the left side, and what's on the right side adds with the right side. Therefore we can do:
1️⃣+2️⃣
2x-3y+5x+3y=25+10
7x=35
x=5
Then we can substitute the value of x back into either of the 2 equations.
2*5-3y=25
10-3y=25
3y=-15
y=-5
Then write the 2 answers together.
{x=5
{
{y=-5
Now we can check our answers.
2*5-3*-5=10- -15= 10+15=25 Correct
5*5+3*-5= 25+ -15= 10 Correct
From this we can see that x=5 y= - 5 are the correct answers!