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GrogVix [38]
3 years ago
7

Can somebody help me with this? Thank you

Mathematics
1 answer:
melomori [17]3 years ago
4 0

Answer:

x≥1 or x≤−3

Step-by-step explanation:

x+1≥2  possibility 1

x+1−1≥2−1  Subtract 1 from both sides

x≥1

x+1≤−2  Possibility 2

x+1−1≤−2−1  Subtract 1 from both sides

x≤−3

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Heart failures are due to either natural occurrences (87%) or outside factors (13%). Outside factors are related to induced subs
kkurt [141]

Answer:

(a) The probability is 9.49%

(b) The probability is 38.28%

Step-by-step explanation:

The probability that a failure is due to induced substance is calculated as a multiplication as:

(13%) * (73%) = 9.49%

Where 13% is the percentage of heart failures that are due outside factors and 73% is the percentage of outside factors that are due induced substances.

On the other hand, the probability that a failure is due to disease or infection is the sum of the probability that a failure is due to disease and the probability that a failure is due to infection.

Then, the probability that a failure is due to disease is calculated as:

(87%) * (27%) =  23.49%

Where 87% is the percentage of heart failures that are due natural factors and 27% is the percentage of natural factors that are due disease.

At the same way, the probability that a failure is due to infection is calculated as:

(87%) * (17%) =  14.79%

So, the probability that a failure is due to disease or infection is:

23.49% + 14.79% = 38.28%

4 0
3 years ago
Find the unknown number in the proportion
Afina-wow [57]
2/3=x/148. First you cross multiply the 148 and 2. with that answer you divide that from 3 to get your x value

Answer: 98.66666666666667
7 0
4 years ago
What is the answer? 4(-x+4)=12 ​
solniwko [45]
The answer is x=1 because you have to distribute and then divide
4 0
3 years ago
In how many ways can the 19 members of a chess club fill the offices of​ King, Knight,​ Bishop, and​ Rook?
goldfiish [28.3K]

Solution:

This problem is a permutation because the order matters here. This means that choosing A as King, B as Knight, C as Bishop and D as Rook results in a different arrangement from B as King, A as Knight, D as Bishop and C as Rook. We would count them both because in the first case A is King, but in the second case A is Knight.

Therefore, the possible number of ways are given below:

19P4=\frac{19!}{(19-4)!} =\frac{19 \times 18 \times 17 \times 16 \times 15!}{15!} =19 \times 18 \times 17 \times 16 =93024

Hence there will be 93024 ways 19 members of a chess club fill the offices of King, Knight, Bishop, and Rook.

3 0
3 years ago
How do I divide this:
n200080 [17]
Is this shape 3d and no offense your 28 you should know this stuff. like im 15 and I know more than u MOHAHA
3 0
3 years ago
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