<h3><u>Answer:</u></h3>

<h3><u>Solution</u><u>:</u></h3>
we are given that , a ladder is placed against a side of building , which forms a right angled triangle . We wre given one side of a right angled triangle ( hypotenuse ) as 23 feet and the angle of elevation as 76 ° . We can find the Perpendicular distance from the top of the ladder go to the ground by using the trigonometric identity:

Here,
- hypotenuse = 23 feet
= 76°- Value of Sin
= 0.97 - Perpendicular = ?





ㅤㅤㅤ~<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u>,</u><u> </u><u>the </u><u>distance </u><u>from </u><u>the </u><u>top </u><u>of </u><u>the </u><u>ladder </u><u>to </u><u>the </u><u>ground </u><u>is </u><u>2</u><u>2</u><u>.</u><u>3</u><u>2</u><u> </u><u>feet </u><u>!</u>

13500 m in 250 s
s is the second rate
deomenator is bottom number in a/b, denomenator is b
13500m/250s
use clculator or something to divide or use head
54m/s
answer is A
Answer:
The area of the circle is 113.0 ft²
Step-by-step explanation:
To solve this problem we need to use the area formula of a circle:
a = area
r = radius = 6ft
π = 3.14
a = π * r²
we replace with the known values
a = π * (6ft)²
a = π * 36ft²
a = 113.04ft²
The area of the circle is 113.04ft²
round to the nearest tenth
a = 113.04ft² = 113.0 ft²
Answer:
x^3-6x^2-10x+100
Step-by-step explanation:
Step 1: Distribute x to (x²-6x+20).
x(x²-6x+20)=x^3-6x^2+20x
Step 2: Distribute 5 to (x²-6x+20).
5(x² − 6x + 20)=5x²-30x+100
Step 3: Combine x^3-6x^2+20x and 5x²-30x+100.
x^3-6x^2-10x+100
hope it helps you <3