You would get 9e+46 so not a real answer, just an estimate of what the answer is.
The answer to the math question
a = 1, b =14 and y-coordinate is 6 when x = 0.
Solution:
Let us first write the equation of a line.
Take the points are (2, 2) and (6, 10).
Slope of the line:
m = 2
Point-slope formula:
y - 10 = 2(x - 2)
y - 10 = 2x - 4
Add 10 on both sides,we get
y = 2x + 6
Equation of a line is y = 2x + 6.
To find (a, 8), substitute x = a and y = 8 in the equation,
8 = 2a + 6
Subtract 6 from both sides, we get
2 = 2a
a = 1
To find (4, b), substitute x = 4 and y = b in the equation,
b = 2(4) + 6
b = 8 + 6
b = 14
Substitute x = o in the equation.
y = 2(0) + 6
y = 6
The y-coordinate is 6 when x = 0.
From the figure, it can be seen that the mage A'B'C' is obtained from the pre-image ABC by translating/shifting the vertices of the image by 7 units to the right and 6 units down.
Therefore, the rule represents the translation from the pre-image, ΔABC, to the image, ΔA'B'C' is <span>(x, y) → (x + 7, y – 6)</span>.
Answer:
(A) with .
(B) with
(C) with
(D) with ,
Step-by-step explanation
(A) We can see this as separation of variables or just a linear ODE of first grade, then . With this answer we see that the set of solutions of the ODE form a vector space over, where vectors are of the form with real.
(B) Proceeding and the previous item, we obtain . Which is not a vector space with the usual operations (this is because ), in other words, if you sum two solutions you don't obtain a solution.
(C) This is a linear ODE of second grade, then if we set and we obtain the characteristic equation and then the general solution is with , and as in the first items the set of solutions form a vector space.
(D) Using C, let be we obtain that it must satisfies and then the general solution is with , and as in (B) the set of solutions does not form a vector space (same reason! as in (B)).