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CaHeK987 [17]
3 years ago
9

Please help Right triangles and trigonometry quiz two on Khan Academy

Mathematics
1 answer:
Sedbober [7]3 years ago
8 0

Answer:

AC = 2.44

Step-by-step explanation:

Reference angle = 26°

Opposite side = AC = ?

Adjacent side = BC = 5

Applying TOA, we have:

Tan 26 = opp/adj

Tan 26 = AC/5

multiply both sides by 5

Tan 26 × 5 = AC

AC = 2.44 (nearest hundredth)

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-4x+2=42how do I solve this problem ​
jeka94

Answer:

x = -10

Step-by-step explanation:

move all the constants (numbers without variables) to one side to get

-4x = 42 - 2

-4x = 40

multiply by -1

4x = -40

divide by 4

x = -10

3 0
3 years ago
Read 2 more answers
In form ax+by+c=0
pav-90 [236]
I don't get you but if you transform the equation to it's standard form, it will be
3x+4y=4
First, Multiply each term by 4:
y(4)=-3x/4(4)+1(4)
4y=-12x/4+4
4y=-3x+4
Now add 3x to both sides of the equation:
4y+3x=-3x+3x+4
3x+4y=0+4
3x+4y=4
5 0
3 years ago
What is the approximate length of arc S on the circle below? Use 3.14 for pi. Round your answer to the nearest tenth.
jeka57 [31]
224 is the times to were it’s put in the outside order inside of it
4 0
3 years ago
Please help!<br> Subtract h + 3 ​​from​ 6h + 1.
cricket20 [7]
6h+1-h+3
=5h+4
because 6h-1h is 5h and 1+3 is 4
4 0
3 years ago
Given the following formula, with A = 27 and t = 3, solve for r. <br> A=p(1+rt)
Nookie1986 [14]

Answer:

<h2>A.r=\frac{27-p}{3p}</h2>

Step-by-step explanation:

The given formula is

A=p(1+rt)

Where A=27 and t=3

To solve for r, first we need to move p

\frac{A}{p}=1+rt

Then, we move the term 1

\frac{A}{p}-1=rt

Finally, we move the factor t

\frac{\frac{A}{p}-1 }{t} =r

Replacing given values, we have

\frac{\frac{27}{p}-1 }{3} =r\\r=\frac{\frac{27-p}{p} }{3} \\r=\frac{27-p}{3p}

Thereofre, the right answer is A.

7 0
3 years ago
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