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3 years ago

What is the 48th term of the arithmetic sequence with this explicit formula?

Mathematics

1 answer:

lora16 [44]3 years ago

7 0

Answer:

-149

Step-by-step explanation:

$a_{n}$ =-11 + (n - 1)(-3)

by observation

when n = 0, $a_{0}$ = 1st term

when n = 1, $a_{1}$ = 2nd term

.....

when n = x, $a_{x}$ = (x+1)th term

hence if we want to find the 48th term, n = 48 - 1 = 47

when n = 47, $a_{47}$ = 48th term

= -11 + (47-1)(-3)

= -11 + 46(-3)

= - 11 - 138

= -149

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What’s the ratio for 40 and 64

NARA [144]

Answer:

5/8, 5:8, or 5 to 8

Step-by-step explanation:

you have to simplify the ratio so you have to figure out what 40 and 64 have in common. tho right away you can assume that they both have 2 in common bcz they are both even so you can divide them both by two and get 20/32, and then you can do it again bcz they are both even again and get 10/16, and then you can do it again bcz they are also both even and get 5/8. now 5 is a prime number so you cant divide it any further so you stop it there. and i put three answers bcz there are three ways to write a ratio

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3 years ago

how to rewrite the function in a different form (factored or vertex) where the answer appears as a number in the equation.

rodikova [14]

We can convert the equation of the line in vector form by imposing i cap ,j cap and k cap with direction ratios.

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In physics, a vector is a quantity with both magnitude and direction. It is often represented by an arrow whose length is proportional to the magnitude of the quantity and whose direction is the same as that of the quantity. Simply subtract the starting point from the terminal point to determine the vector in component form given the initial and terminal points.

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8 0

2 years ago

Martin throws a ball straight up in the air. the equation h(t) = -16t^2 + 40t + 5 gives the height of the ball, in feet, t secon

Lisa [10]

Answer:

2.62 seconds

Step-by-step explanation:

Let

t ----> the time in seconds

h(t) ----> he height of the ball, in feet

we have

$h(t)=-16t^2+40t+5$

we know that

When the ball hits the ground, the height is equal to zero

$-16t^2+40t+5=0$

The formula to solve a quadratic equation of the form

$at^{2} +bt+c=0$

is equal to

$t=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-16t^2+40t+5=0$

$a=-16\\b=40\\c=5$

substitute in the formula

$t=\frac{-40\pm\sqrt{40^{2}-4(-16)(5)}} {2(-16)}$

$t=\frac{-40\pm\sqrt{1,920}} {-32}$

$t=\frac{-40+\sqrt{1,920}} {-32}=-0.12\ sec$

$t=\frac{-40-\sqrt{1,920}} {-32}=2.62\ sec$

therefore

The solution is t=2.62 seconds

4 0

3 years ago

What must be a factor of the polynomial function f(x) graphed on the coordinate plane below?

Mamont248 [21]

Answer: D.

Step-by-step explanation:

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3 years ago

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4 0

3 years ago