Using limits, it is found that the infinite sequence converges, as the limit does not go to infinity.
<h3>How do we verify if a sequence converges of diverges?</h3>
Suppose an infinity sequence defined by:
Then we have to calculate the following limit:
If the <u>limit goes to infinity</u>, the sequence diverges, otherwise it converges.
In this problem, the function that defines the sequence is:
Hence the limit is:
Hence, the infinite sequence converges, as the limit does not go to infinity.
More can be learned about convergent sequences at brainly.com/question/6635869
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Answer:
make all the numbers have the same denominator, then simply see what multiplies to equal both fractions. your answer should be -3/10(1/5k+1)
Step-by-step explanation:
Answer:
Two points on the graph would be (2,-1) and (4,2).
Step-by-step explanation:
You can choose two random x variables such as how i selected 2 and 4. if you change the variable x to those values you can solve for y or in this case f(x).
EX:
3/2*2-4
6/2-4
3-4
f(x)= -1
Answer:
2a
Step-by-step explanation:
using distance formula:
√(x₂-x₁)² + (y₂-y₁)²
putting values,
√{a-(a)}² + {b-b}² = √ {a+a}² + 0²
= √(2a)² = √4a² = 2a
Hope this helps:)
(f+g)(x) = f(x) + g(x)
(f+g)(x) = [ f(x) ] + [ g(x) ]
(f+g)(x) = [ 3x-2 ] + [ 2x+1 ]
(f+g)(x) = (3x+2x) + (-2+1)
(f+g)(x) = 5x - 1
Answer is choice B
