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2 years ago

I really need help if somebody could explain this into detail and show me how would really appreciate it please

Mathematics

2 answers:

sleet_krkn [62]2 years ago

4 0

Top guy correct (MARK HIM Brainiest)

marishachu [46]2 years ago

3 0

Answer: y = (5x)^2

Step-by-step explanation: You're finding the inverse.

f(x) = $\sqrt{x}$ /5 --> y = $\sqrt{x}$ /5 (they mean the same thing)
x = $\sqrt{y}$ /5 (switch x and y)
5x = $\sqrt{y}$ (multiple both sides by 5)
(5x)^2 = y (square both sides) --> the first answer choice

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In triangles ABC and LMN, ∠A ≅ ∠L, ∠B ≅ ∠M, and ∠C ≅ ∠N. Is this information sufficient to prove triangles ABC and LMN congruent

ipn [44]

Answer:

Step-by-step explanation:

No. We have 3 angles of triangle ABC congruent to 3 corresponding angles of triangle LMN. That is AAA. To use ASA, you need two angles and an included side. With three angles, you can prove the triangles similar, but not congruent.

5 0

1 year ago

(ASAP PICTURE ADDED) What is the simplified form of the following expression?

bonufazy [111]

Answer:

option c is correct.

Step-by-step explanation:

$7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{16x}\right)-3\left(\sqrt[3]{8x}\right)$

WE need to simplify this equation.

Solve the parenthesis of each term.

$=7\left\sqrt[3]{2x}\right-3\left\sqrt[3]{16x}\right-3\left\sqrt[3]{8x}\right$

Now, We will find factors of the terms inside the square root

factors of 2: 2

factors of 16 : 2x2x2x2

factors of 8: 2x2x2

Putting these values in our equation: $=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2X2 x}\right)-3\left(\sqrt[3]{2X2X2 x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3*2\left(\sqrt[3] {2 x}\right)-3*2\left(\sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)$

Adding like terms we get:

$=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right\\=(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\$

$(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\can\,\,be \,\, written\,\, as\,\,\\(\sqrt[3] {2x})-6\left(\sqrt[3]{x}\right)$

So, option c is correct

5 0

2 years ago

Read 2 more answers

1. Fruits are taken successfully from a bag containing 6 avocados, 4 bananas and 5

victus00 [196]

Total 15

6+4=10+5=15

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7 0

2 years ago

Find the value of x so that the function has the given value. <br> q(x)=12x−3; q(x)=−4

Anna [14]

Answer:

$- \frac{1}{ 12}$

Step-by-step explanation:

since q(x)=-4

substitute

hence

-4=12x-3

take -3 to the other side where it becomes positive

therefore

-1=12x

divide by 12

you will get the above answer

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2 years ago

Which fraction is in reduced form?

kompoz [17]

Answer:

C 5/13

Step-by-step explanation:

A fraction is written in reduced form if there are no common factors in the numerator and denominator. Since you know your multiplication tables, you can easily identify the common factors:

A 20 = 5·4, so 4 is a common factor 4/(4·5) = 1/5

B 6 = 2·3, 9 = 3·3, so 3 is a common factor (2·3)/(3·3) = 2/3

C 13 is not a multiple of the prime number 5, so there are no common factors. 5/13 is a reduced fraction

D 14 = 2·7, 21 = 3·7, so 7 is a common factor (2·7)/(3·7) = 2/3

8 0

3 years ago