Find the area of a triangle with a base length of 3 units and a height of 4 units.
2 answers:
Answer:
square units
Step-by-step explanation:
The area of a triangle can be calculated by multiplying the triangle's base by its height, and then dividing the result by . As an algebraic expression, this would be
, where
is the triangle's base and
is the triangle's height. In this case, we know that
and
. Therefore, the area of this triangle is
square units. Hope this helps!
You might be interested in
Answer:
Point of intersection (-11/3 , 1/3)
All distances from the vertices are
Step-by-step explanation:
The vertices of the triangle is A(-3,5) , B (1,1) and C (-7,-3)
We need to find the perpendicular bisector of the triangle first
let's take one side connecting A and B
mid point of A and B = (-1,3)
Slope of the line joining A and B = -1
slope of perpendicular to line joining A and B = 1
equation of line passing through (-1,3) with slope 1
y - 3 = 1(x-(-1))
y -3 = x+1
x-y = -4 ............(1)
similarly
mid point joining B and C = (-3,-1)
slope perpendicular to line joining B and C = -2
Equation of perpendicular bisector of line joining B and C =
y +1 = -2(x +3 )
y+1 = -2x -6
2x+y = -7 ..........(2)
On solving 1 and 2
x= -11/3 , y= 1/3
Distances
From A =
From B =
From C =
Answer:
cosA =
Step-by-step explanation:
cosA = =
=