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Svetach [21]
2 years ago
15

5. What is the value of the expression [(29 + 18) + (17 - 8)] = 8?

Mathematics
2 answers:
german2 years ago
8 0

Answer:

(29 + 18)   +    (17 - 8) = ?

     ∨                 ∨

     47       +        9     =  ?

          ? = 56             i think i tried

Step-by-step explanation:

uysha [10]2 years ago
5 0
I'm not sure what exactly the question is asking for, but the value if this expression should be 56.

Add what are in the parentheses, 29+18=47 and 17-8=9.
Then add up those values, 47+9=56.

Comment on this post if I understood the question incorrectly.
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8 0
3 years ago
Read 2 more answers
A fully inflated basketball has a radius of 12
valentinak56 [21]

The volume of air needed is equal to the volume of the sphere, which is 7,234.56 cm^3.

<h3>How to get the volume of a sphere?</h3>

The volume of air that we need is equal to the volume of the basketball.

Remember that for a sphere of radius R, the volume is:

V = (4/3)*3.14*R^3

In this case, the radius is 12cm, replacing that we get:

V = (4/3)*3.14*(12cm)^3 = 7,234.56 cm^3

Then, to fully inflate the ball, we need  7,234.56 cm^3 of air.

If you want to learn more about spheres, you can read:

brainly.com/question/10171109

7 0
2 years ago
Find the mid point of PQ if P (0,0) and Q (5, 12)
Simora [160]
Using the midpoint formula we get:

(x,y)=(0+5/2, 0+12/2) or (5/2, 6) as the midpoint.
5 0
3 years ago
1+1 equals what i don't know big prize i give all my brainy points i just graduated don't need this anymore
Marina86 [1]

\huge \mathbb \pink{HELLO }

\sf \green{1  + 1 \: is \: 2}

\huge \mathcal \orange{HAVE \: A \: GOOD \: DAY }

6 0
1 year ago
Consider the differential equation <img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%3D6%20y%5E%7
Nutka1998 [239]
As a Bernoulli equation:

x^2\dfrac{\mathrm dy}{\mathrm dx}=6y^2+6xy\iff x^2y^{-2}\dfrac{\mathrm dy}{\mathrm dx}-6xy^{-1}=6

Let z=y^{-1}\implies\dfrac{\mathrm dz}{\mathrm dx}=-y^{-2}\dfrac{\mathrm dy}{\mathrm dx}. The ODE becomes

-x^2\dfrac{\mathrm dz}{\mathrm dx}-6xz=6
x^6\dfrac{\mathrm dz}{\mathrm dx}+6x^5z=-6x^4
\dfrac{\mathrm d}{\mathrm dx}[x^6z]=-6x^4
x^6z=-6\displaystyle\int x^4\,\mathrm dx
x^6z=-\dfrac65x^5+C
z=-\dfrac6{5x}+\dfrac C{x^6}
y^{-1}=-\dfrac6{5x}+\dfrac C{x^6}
y=\dfrac1{\frac C{x^6}-\frac6{5x}}
y=\dfrac{5x^6}{C-6x^5}

With y(3)=6, we get

6=\dfrac{5(3)^6}{C-6(3)^5}\implies C=\dfrac{4131}2

so the solution is

y=\dfrac{5x^6}{\frac{4131}2-6x^5}=\dfrac{10x^6}{4131-12x^5}

which is valid as long as the denominator is not zero, which is the case for all x\neq\sqrt[5]{\dfrac{4131}{12}}.
8 0
3 years ago
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