I'm assuming a 5-card hand being dealt from a standard 52-card deck, and that there are no wild cards.
A full house is made up of a 3-of-a-kind and a 2-pair, both of different values since a 5-of-a-kind is impossible without wild cards.
Suppose we fix both card values, say aces and 2s. We get a full house if we are dealt 2 aces and 3 2s, or 3 aces and 2 2s.
The number of ways of drawing 2 aces and 3 2s is

and the number of ways of drawing 3 aces and 2 2s is the same,

so that for any two card values involved, there are 2*24 = 48 ways of getting a full house.
Now, count how many ways there are of doing this for any two choices of card value. Of 13 possible values, we are picking 2, so the total number of ways of getting a full house for any 2 values is

The total number of hands that can be drawn is

Then the probability of getting a full house is

Answer:
the function is either increasing or decreasing
Step-by-step explanation:
For m ≠ 0, the function must be either increasing or decreasing. If the function is increasing, it will have its maximum value at the right end of the interval. If it is decreasing, its maximum value will be at the left end of the interval.
Answer:
1) x³-y³ = (x-y)(x²-xy+y²)
2)x²-y² =(x-y)(x+y)
3)x-y = (x-y)
hcf = (x-y)
lcm = (x-y)(x²-xy+y²)(x+y)= (x³-y³)(x+y)
Step-by-step explanation:
Answer:

As this value is definite (has an end), it would be considered rational.