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aleksandr82 [10.1K]
3 years ago
10

What is the sum os the interior angles of the polygon?

Mathematics
1 answer:
RSB [31]3 years ago
4 0
To find the suum the formula is (n - 2) x 180 degrees
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Toni rides the Ferris wheel shown for 15 revolutions. A photo of a Ferris wheel has the diameter labeled fifty-six feet. Questio
NARA [144]

Answer:

a. 176 feet b. 2640 feet

Step-by-step explanation:

a. Since the diameter of the Ferris wheel is D = 56 feet, the distance Toni travels in one revolution is the circumference of the Ferris wheel, C = πD.

So C = 22/7 × 56 ft = 22 × 8 ft = 176 feet

b. The distance traveled in 15 revolutions is thus D' = 15 × distance of one revolution = 15 × 176 = 2640 feet

5 0
3 years ago
Write the standard equation of the circle below.
s344n2d4d5 [400]

Answer:

The first answer is correct.

(x + 1)^2 + (y - 2)^2 = 1

A circle with the midpoint M(Mx, My) and the radius r can be written as

(x - Mx)^2 + (y - My)^2 = r^2


7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%2018-%20%5Csqrt%202" id="TexFormula1" title="\sqrt 18- \sqrt 2" alt="\sqrt 18- \sqrt 2
zimovet [89]
The answer is 2√2

√18 - √2
3 √2 - √2 = 2√2
4 0
2 years ago
Read 2 more answers
2x squared + 9x=-5 i need to solve for x
In-s [12.5K]
2x^2+ 9x=-5 \\ \\2x^2 + 9x+5 =0 \\\\a=2, \ \ b=9 , \ \ c=5 \\\\\Delta =b^2-4ac = 9^2 -4\cdot 2\cdot 5 =  81-40=41 \\ \\x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{-9-\sqrt{41}}{2\cdot 2 }=\frac{-9-\sqrt{41}}{ 4 }\\\\ x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{-9+\sqrt{41}}{2\cdot 2 }=\frac{-9+\sqrt{41}}{4 }
3 0
3 years ago
What is the power dissipated by a 5ohm resistor if the current is 4A?​
posledela

Answer:

Answer: First, we use Ohm's law ( V = I × R ), to find the current through the resistor. The voltage across the resistor is V = 9 V. The resistance of the resistor is R = 100 Ω. Then, we can use the power rule ( P = I × V ), to find the power dissipated by the resistor

Step-by-step explanation:

i dont know if its the right answer but here

6 0
2 years ago
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