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Mariana [72]
3 years ago
13

A teacher earns 25000 a year and receives a 4% cost of living increase in salary and a $275 merit increase. His salary increased

by
a. 4.5%
b. 4.9%
c. 5.0%
d. 5.1%
e. 5.2%
solve how you got it
Mathematics
1 answer:
Alexus [3.1K]3 years ago
5 0

Answer:

The asnwer is a. 4.5%

Step-by-step explanation:

.05 * 25000 + $275 = 4.5

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1100

Step-by-step explanation:

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3 years ago
Two horses are ready to return to their barn after a long workout session at the track. the horses are at coordinates H(1,10) an
olya-2409 [2.1K]
The given information are the coordinates of points H, Z and B. So, the first step to do is to plot these points on a Cartesian plane as shown in the attached picture. We can deduce visually that horse Z is closer to the barns than horse H. But, to further justify the answer, we have to provide the magnitude of the distance of horses H and Z to barn B. In this approach, we use the distance formula:

d = √(x₂ - x₁)² + (y₂ - y₁)²

Use the coordinates of the two points to know their linear distances. These are represented by the red and green lines for each of the horses.

Distance between H and B = √(⁻3 - 1)² + (⁻9-10)²
Distance between H and B = √(⁻3 - 1)² + (⁻9-10)²
Distance between H and B  = 19.4165

Since the scale is 1 unit = 100 meters, the actual distance between horse H and barn B is 19.416*100 = 1,941.65 meters


Distance between Z and B = √(⁻3 - 10)² + (⁻9-1)²
Distance between Z and B = √(⁻3 - 10)² + (⁻9-1)²
Distance between Z and B  = 16.4012

Since the scale is 1 unit = 100 meters, the actual distance between horse Z and barn B is 16.4012*100 = 1,640.12 meters

Comparing the distances: 1,941.65 meters > 1,640.12 meters. Therefore, it justifies that horse Z is nearer to the barn.

4 0
4 years ago
rectangle ABCD is graphed in the cordinate plane. The following are the verticies of the rectangle; A(-6,-4),B(-4,-4),C(-4,-2),
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Answer:

Therefore Perimeter of Rectangle ABCD is 4 units

Step-by-step explanation:

Given:

ABCD is a Rectangle.

A(-6,-4),

B(-4,-4),

C(-4,-2), and

D (-6,-2).

To Find :

Perimeter of Rectangle = ?

Solution:

Perimeter of Rectangle is given as

\textrm{Perimeter of Rectangle}=2(Length+Width)

Length = AB

Width = BC

Now By Distance Formula  we have'

l(AB) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}

Substituting the values we get

l(AB) = \sqrt{((-4-(-6))^{2}+(-4-(-4))^{2} )}

l(AB) = \sqrt{((2)^{2}+(0)^{2} )}=2\ unit

Similarly

l(BC) = \sqrt{((-4-(-4))^{2}+(-2-(-4))^{2} )}

l(BC) = \sqrt{((0)^{2}+(2)^{2} )}=2\ unit

Therefore now

Length = AB = 2 unit

Width = BC = 2 unit

Substituting the values  in Perimeter we get

\textrm{Perimeter of Rectangle}=2(2+2)=2(4)=8\ unit

Therefore Perimeter of Rectangle ABCD is 4 units

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hshsjwhwjwjuwubwbwwuwhquuwqjqjqkqbqv pangit mo potang ina mo bulok wlang silbe wag kana mag ajabajajajqkqjbqiqiq

8 0
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