Answer: Total amount of money earned last month = $2608.75
Step-by-step explanation:
Miguel earns 2,456.75 every month. This is his constant pay for the month. He also earns an extra 4.75 every time he sells a new gym membership.
Last month, Miguel sold 32 new gym membership. This means that the extra money that he earned for last month will be the number of new gym membership sold times the amount her earns per new gym membership sold. It becomes
32 × 4.75 = 152
Total amount of money earned last month will be sum of his monthly salary + the extra earned. It becomes
2456.75 + 152 = $2608.75
Step-by-step explanation:
We can break this up into pieces, first we do, 7/8 - 1/4, find the least common denominator which is 8, so the equation will be 7/8 - 2/8, which we can now subtract and will give us, 5/8, now that we have done that, we can do 5/8 - 1/2. Since we know that half of 8 (our denominator) is 4. Then the equation would be 5/8 - 4/8, which brings us to 1/8 as our final answer.
Cheers!
The number of tickets sold on Friday were 66 children tickets and 97 adult tickets.
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
Let x represent the number of children and y represent the number of adult, hence:
5.2x + 9.9y = 1303.5 (1)
Also:
x + y = 163 (2)
From both equations:
x = 66, y = 97
The number of tickets sold on Friday were 66 children tickets and 97 adult tickets.
Find out more on equation at: brainly.com/question/2972832
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Answer:
3).
4).
If it was by 10, k = 3 by 10
k = 30
5).
Answer:
![\sqrt[3]{0.95} \approx 0.9833](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.95%7D%20%5Capprox%200.9833)
![\sqrt[3]{1.1} \approx 1.0333](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1.1%7D%20%5Capprox%201.0333)
Step-by-step explanation:
Given the function: ![g(x)=\sqrt[3]{1+x}](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7B1%2Bx%7D)
We are to determine the linear approximation of the function g(x) at a = 0.
Linear Approximating Polynomial,
a=0
![g(0)=\sqrt[3]{1+0}=1](https://tex.z-dn.net/?f=g%280%29%3D%5Csqrt%5B3%5D%7B1%2B0%7D%3D1)
Therefore:
(b)![\sqrt[3]{0.95}= \sqrt[3]{1-0.05}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.95%7D%3D%20%5Csqrt%5B3%5D%7B1-0.05%7D)
When x = - 0.05
(c)
(b)![\sqrt[3]{1.1}= \sqrt[3]{1+0.1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1.1%7D%3D%20%5Csqrt%5B3%5D%7B1%2B0.1%7D)
When x = 0.1
