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Kitty [74]
3 years ago
5

What is the length of the unknown side of the right triangle?

Mathematics
1 answer:
a_sh-v [17]3 years ago
3 0

Answer:

7 O ⋅ ( 24 h O ) ⋅ ( 25 O ) ⋅ 31 . X ⋅ 7 = 7 X 24 = 7 X 7 O ⋅ ( 24 h O ) ⋅ ( 25 O ) ⋅ 31 = 130200 O 3 h

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2= d-11/3 <br><br> 100 points if u answer pls help asap
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Answer:

i hope this works

Step-by-step explanation:

d=17/3

d=5.666

d=5 2/3

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Can someone help fast to find a and c
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Step-by-step explanation:                        

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What are independent and dependent variables?
Nonamiya [84]
I'm pretty sure this doesn't belong in mathematics but this belongs to science. Anyways.. an independent variable is the only variable that is being changed. The dependent variable is what you find out- in other words it is the outcome.

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5 times a number is less than 2 times that same number minus 9, what must be the value of the number?
zzz [600]
EQUATION: 5x = 2x - 9
Add 9 to both sides
NEW EQUATION: 5x + 9 = 2x
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NEW EQUATION: 9 = -3x
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NEW EQUATION: -3 = x, or x=-3
5 0
4 years ago
Triangle ABC is formed by the vertices A(1,2,-1), B(-3,-6,2)and C(3,-2,0).
Vesnalui [34]

Answer:

Point D: (0,-4, 1 )

<em>d</em> = √41

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Pre-Calculus</u>

  • Midpoint Formula [3D]: (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}, \frac{z_1+z_2}{2} )
  • Distance Formula [3D]: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point A(1, 2, -1)

Point B(-3, -6, 2)

Point C(3, -2, 0)

<u>Step 2: Find Point D</u>

Simply plug in your coordinates B and C into the midpoint formula to find midpoint

  1. Substitute [MF]:                    (\frac{-3+3}{2},\frac{-6-2}{2}, \frac{2+0}{2} )
  2. Add/Subtract:                       (\frac{0}{2},\frac{-8}{2}, \frac{2}{2} )
  3. Divide:                                  (0,-4, 1 )

<u>Step 3: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates A and D into the distance formula to find distance <em>d</em>

  1. Substitute [DF]:                    d = \sqrt{(0-1)^2+(-4-2)^2+(1+1)^2}
  2. Subtract/Add:                       d = \sqrt{(-1)^2+(-6)^2+(2)^2}
  3. Exponents:                           d = \sqrt{1+36+4}
  4. Add:                                      d = \sqrt{41}
5 0
3 years ago
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