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Andrej [43]
4 years ago
12

Two angels whose sides are opposite rays are called___ angles. Two coplanar angles with a common side, a common vertex, and no c

ommon interior points are called___ angles.
a. adjacent; vertical
b. adjacent; complementary
c. vertical; adjacent
d. vertical; supplementary
Mathematics
1 answer:
Amanda [17]4 years ago
7 0
Answer choice C ;) this is yukki aproved

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Name the quadrilateral whose diagonals are perpendicular bisectors of each other
dexar [7]

Rhombus or square.

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3 years ago
Find the inverse of the matrix <img src="https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-2%5C%5C-10%269%5C%5C
valentinak56 [21]

Answer:

The answer is (b)

Step-by-step explanation:

* Lets check how to find the inverse of the matrix,

 its dimensions is 2 × 2

* To know if the inverse of the matrix exist find the determinant

- If its not equal 0, then it exist

* How to find the determinant

- It is the difference between the multiplication of

 the diagonals of the matrix

Ex: If the matrix is \left[\begin{array}{ccc}a&b\\c&d\end{array}\right]

     its determinant = ad - bc

- After that lets swap the positions of a and d, put negatives

 in front of b and c, and divide everything by the determinant

- The inverse will be \left[\begin{array}{ccc}\frac{d}{ad-bc} &\frac{-b}{ad-bc}\\\frac{-c}{ad-bc} &\frac{a}{ad-bc}\end{array}\right]

* Lets do that with our problem

∵ The determinant = (9 × 9) - (-2 × -10) = 81 - 20 = 61

- The determinant ≠ 0, then the inverse is exist

∴ The inverse is \frac{1}{61}\left[\begin{array}{ccc}9&2\\10&9\end{array}\right]=

   \left[\begin{array}{ccc}\frac{9}{61}&\frac{2}{61}\\\frac{10}{61} &\frac{9}{61}\end{array}\right]

* The answer is (b)

7 0
3 years ago
For the school play, the advance tickets cost $3, while tickets at the door cost $5. Thirty more tickets were sold at door in ad
Talja [164]

Answer:

<u>310</u> tickets were sold in advance before school pay and <u>340</u> door tickets were sold in advance.

Step-by-step explanation:

Given:

Let number of tickets sold in advance be 'x'.

Cost of advance ticket = $3

Cost of door tickets = $5

Also given:

Thirty more tickets were sold at door in advance

Hence number of door tickets sold = x+30

Total Money Collected = $2630

Now we can say that Total Money Collected is equal to sum of number of tickets sold in advance multiplied by Cost of advance ticket and number of door tickets sold multiplied by Cost of door tickets.

Framing in equation form we get;

3x+(x+30)5=2630

Solving the equation to find the value of x we get;

3x+5x+150=2630

Combining the like terms we get;

3x+5x=2630-150\\\\8x= 2480

Now Dividing 8 on both side using division property we get;

\frac{8x}{8} =\frac{2480}{8}\\ \\x=310

Substituting the value of x to find number of door tickets been sold.

number of door tickets sold = x+30=310+30 =340

Hence, <u>310</u> tickets were sold in advance before school pay and <u>340</u> door tickets were sold in advance.

8 0
3 years ago
Pls help :( The graph shows the relationship between a puppy’s weight y, in ounces, and time x, in months, as it grows. Which fu
Ulleksa [173]

Answer:

c y=6x+4

Step-by-step explanation:

y=mx+b.  m= slope b= y intercept

at x=0, the graph is at y=4, so that is b. Slope is up/over. so from point (0,4) to point (2,16), the graph went up 12 and over 2. 12/2=6

4 0
3 years ago
What is equal to 16x squared-144??
anyanavicka [17]
I hope this helps you

4 0
3 years ago
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