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3 years ago

If 7 litres of petrol cost $14.70 ,calculate the cost of 15 litres of petrol Kindly answer

Mathematics

1 answer:

erastovalidia [21]3 years ago

3 0

Answer:

The cost of 15 liters is $31.50

Step-by-step explanation:

1. Find the price for 1 liter of petrol.

Divide the cost by the number of liters:

$14.70 / 7 = $2.10 per liter.

2. Multiply the price for 1 liter by the new number of liters, 15.

$2.10 per liter x 15 liters = $31.50

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Answer:

x = 16

Step-by-step explanation:

The figure shown shows an inscribed angle F and central angle E. Both angles intercept the same arc.

Therefore, angle E is twice the measure of angle F, according to the central angle theorem of a circle.

Thus,

m<E = 2 * m<F

(x + 94)° = 2(55)

We can find the value of x with this equation.

x + 94 = 110

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3 years ago

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Answer:

slope=4

Step-by-step explanation:

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3 years ago

Round to the nearest hundredth: 2.0625

AURORKA [14]

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3 years ago

Read 2 more answers

Write words to match expression 24 divided by 6

miv72 [106K]

twenty four divisible by six, if that what u meant . or 24÷6

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3 years ago

<img src="https://tex.z-dn.net/?f=0%20%3D%20%20%20-%204.9t%20%7B%7D%5E%7B2%7D%20%20%2B%2027t%20%2B%202.4" id="TexFormula1" title

marta [7]

$0 = - 4.9t {}^{2} + 27t + 2.4$
Convert decimals to fractions

$0 = - \frac{49}{10} t {}^{2} + 27t + \frac{12}{5}$
Multiply both sides by 10

$0 = - 49t {}^{2} + 270t + 24$
Move expression to the left.

$0 + 49t {}^{2} - 270t - 24 = 0$
Remove zero.

$49t {}^{2} - 270t - 24 = 0$ Solve the quadratic equation.

$t = \frac{ - ( - 270) + - \sqrt{( - 270) {}^{2} - 4 \times 49 \times ( - 24) } }{2 \times 49}$
Remove parenthesis and calculate.

$t = \frac{270 + - \sqrt{72900 + 4704} }{98}$
Add the numbers

$t = \frac{270 + - 77604}{98}$
Separate the solutions

$t = \frac{270 + \sqrt{77604} }{98} \\ t = \frac{270 - \sqrt{77604} }{98}$
The final solution are
$t1 = \frac{270 - \sqrt{77604} }{98} , t2 = \frac{270 + \sqrt{77604} }{98}$

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3 years ago