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Verdich [7]
3 years ago
13

If the terminal side of angle 0 in standard position intersects the unit circle at p (3/5,4/5). Find cos0 and sin0

Mathematics
1 answer:
Rina8888 [55]3 years ago
3 0

Answer:

\sin \theta = \frac{4}{5}, \cos \theta = \frac{3}{5}

Step-by-step explanation:

Let be P(x,y) = \left(\frac{3}{5}, \frac{4}{5}  \right) the end of the terminal side of angle \theta in standard position, that is, an angle measured with respect to +x semiaxis. By Trigonometry, we know that the sine and the cosine of the angle are, respectively:

\sin \theta = \frac{y}{\sqrt{x^{2} + y^{2}}} (1)

\cos \theta = \frac{x}{\sqrt{x^{2}+y^{2}}} (2)

If we know that x = \frac{3}{5} and y = \frac{4}{5}, then the sine and the cosine of the angle are:

\sin \theta = \frac{\frac{4}{5} }{\sqrt{\left(\frac{3}{5} \right)^{2}+\left(\frac{4}{5} \right)^{2}}}

\sin \theta = \frac{4}{5}

\cos \theta = \frac{\frac{3}{5} }{\sqrt{\left(\frac{3}{5} \right)^{2}+\left(\frac{4}{5} \right)^{2}}}

\cos \theta = \frac{3}{5}

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3 years ago
How do you factorize p2 + 2p - 3 =0
julia-pushkina [17]

Answer:

Solution

p = {-3, 1}

Step-by-step explanation:

Simplifying

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Solving for variable 'p'.

Factor a trinomial.

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Subproblem 1

Set the factor '(-3 + -1p)' equal to zero and attempt to solve:

Simplifying

-3 + -1p = 0

Solving

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Move all terms containing p to the left, all other terms to the right.

Add '3' to each side of the equation.

-3 + 3 + -1p = 0 + 3

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Combine like terms: 0 + 3 = 3

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Divide each side by '-1'.

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Simplifying

p = -3

Subproblem 2

Set the factor '(1 + -1p)' equal to zero and attempt to solve:

Simplifying

1 + -1p = 0

Solving

1 + -1p = 0

Move all terms containing p to the left, all other terms to the right.

Add '-1' to each side of the equation.

1 + -1 + -1p = 0 + -1

Combine like terms: 1 + -1 = 0

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Combine like terms: 0 + -1 = -1

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Divide each side by '-1'.

p = 1

Simplifying

p = 1

Solution

p = {-3, 1}

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