Question

PLEASE HELPPPP quickly

Answer 1

Answer:

a = 25

b= 1

$25(1 + \sqrt{2} )$

-Expand the brackets first

-than rationalise , to remove the square root from the denominator.

-lastly, simplify.

Hope I was able to help:)))

Answer 2

Answer:

$\boxed{25}( \boxed{1} + \sqrt{2} )$

Step-by-step explanation:

$\frac{ {( \sqrt{32} + \sqrt{2} })^{2} }{ \sqrt{8} - 2} \\ \\ = \frac{ {( 4\sqrt{2} + \sqrt{2} })^{2} }{2 \sqrt{2} - 2} \\ \\ = \frac{ { {( \sqrt{2} )}^{2} ( 4 + 1 })^{2} }{2 (\sqrt{2} - 1)} \\ \\ = \frac{ { {2 ( 5} })^{2} }{2 (\sqrt{2} - 1)} \\ \\ = \frac{ 25 }{ (\sqrt{2} - 1)} \\ \\ = \frac{ 25( \sqrt{2} + 1) }{ (\sqrt{2} - 1)( \sqrt{2} + 1)} \\ \\ = \frac{ 25(\sqrt{2} + 1)}{ (\sqrt{2}) ^{2} - {(1)}^{2} )} \\ \\ = \frac{ 25(\sqrt{2} + 1)}{2 - 1} \\ \\ = \frac{ 25(\sqrt{2} + 1)}{1} \\ \\ = \boxed{25}( \boxed{1} + \sqrt{2} )$