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3 years ago

What value of c makes the equation true? 34 = 6 + 4c

Mathematics

2 answers:

blagie [28]3 years ago

8 0

Answer:

Step-by-step explanation:

34-6=28

28/4=7

c=7

Snowcat [4.5K]3 years ago

6 0

Answer:

The answer would be 'c=7'.

Step-by-step explanation:

I hope this was helpful, have a blessed day.

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An archaeologist is categorizing the artifacts he has discovered. Two-thirds of the artifacts are shards of pottery. One-eighth

Reika [66]

Answer:

Personal items=15

Step-by-step explanation:

We are given:

Total number of artifacts = 72.

We are told that 2/3 of total artifacts are shards of pottery.

$\text{Shards of pottery}=72*\frac{2}{3} =24*2=48$

We are also told that 1/8 of total artifacts are tools.

$\text{Tools}=72*\frac{1}{8}=9$

Now we will find out number of personal items by subtracting combined number of shards of pottery and tools from total number of artifacts.

$\text{ Personal items}=72-(48+9)$

$\text{ Personal items}=72-57=15$

Therefore, there are 15 personal items.

8 0

3 years ago

Krissi has $14 in the bank and earns $8 a day. John has 35$ and earns $5 a day when will krissi have more money?

SOVA2 [1]

Answer: 8 days

Step-by-step explanation:

K=14+8x

J=35+5x

when K=J they will have the same amount

14+8x=35+5x

8x=21+5x

3x=21

x=7 days until they have the same amount- 8 days until she has more

5 0

2 years ago

Find the next four terms of the sequence 5, 4, 9, 13, 22

Ganezh [65]

Hello,

It is the Fibonacci 's suit.

$u_1=5\\u_2=4\\u_3=u_1+u_2=5+4=9\\u_4=u_2+u_3=4+9=13\\u_5=u_3+u_4=9+13=22\\u_6=13+22=35\\u_7=22+35=57\\u_8=35+57=92\\u_9=57+92=149\\\\\\\boxed{u_{n+2}=u_{n}+u_{n+1}}\\$

8 0

2 years ago

What is the value of b?<br> 50 points in it for you plus a thanks, 5 star and brainliest.

Amiraneli [1.4K]

Answer:

Step-by-step explanation:

4 0

3 years ago

Which would be the best method to use to solve the following equations? Explain your reasoning.

o-na [289]

A. square root property

$3x^2-192=0\\x^2-66=0\\x^2=66\\x= -\sqrt{66} or \sqrt{66}$

it has one value with x which is x^2 and it cn be easily solved without having to factorise, quadratic formula cant be used as it need ax^2+bx+c=0 format

B. factorising

$x^2-x-6=0\\x^2+2x-3x-6=0\\(x+2)(x-3)=0\\x+2=0 and x-3=0\\x= -2 \\x= 3$

i just felt like this was easier to factorise than the other 2 options left

C. Completing the square

$x^2-6x-7=0\\(x-3)^2=0\\x= -1\\x= 7$

same reason personal preference

D- Quadratic

$x^2-17x-7=0\\x=\frac{-(-17)+\sqrt{(-17)^2-4(1)(-7)} }{2(1)} \\x=\frac{-(-17)-\sqrt{(-17)^2-4(1)(-7)} }{2(1)}\\x=17.4\\x=-0.402$

the 17 kinda threw me off and i didnt wanna get on factorising or doing completing the square so quadratic formal

7 0

2 years ago