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3 years ago

What value of c makes the equation true? 34 = 6 + 4c

Mathematics

2 answers:

blagie [28]3 years ago

8 0

Answer:

Step-by-step explanation:

34-6=28

28/4=7

c=7

Snowcat [4.5K]3 years ago

6 0

Answer:

The answer would be 'c=7'.

Step-by-step explanation:

I hope this was helpful, have a blessed day.

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This is urgent!!!!!!!!!!!!!!!!!!!!

Debora [2.8K]

Answer:

i am not completely sure but i believe the second or third one is the options, sorry i wish i could help more

Step-by-step explanation:

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3 years ago

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What is 4.908 in expanded form

velikii [3]

Answer:

4.908

Step-by-step explanation:

Expanded Notation Form:

+ 0.9

+ 0.00

+ 0.008

Expanded Factors Form:

4 × 1

+ 9 × 0.1

+ 0 × 0.01

+ 8 × 0.001

Expanded Exponential Form:

4 × 100

+ 9 × 10-1

+ 0 × 10-2

+ 8 × 10-3

Word Form:

four and nine hundred eight thousandths

3 0

3 years ago

A 20-pound bag of dog food costs $16. What is the unit price per pound?

ch4aika [34]

Answer:

0.8

Step-by-step explanation:

To calculate the cost of any item per pound, divide the cost of the item by its weight in pounds: cost ÷ pounds = cost per pound.

Hope This Helped!!

6 0

3 years ago

Could you explain how to solve this problem? 10n = 40

irina1246 [14]

Since were trying to solve for n, you have to isolate it so you would divide both sides by 10, and that will give you n = 4

7 0

2 years ago

Read 2 more answers

The path of a volley ball thrown over a net is modeled with the function A(x) = -0.02x2 + 0.6x + 5, where x is

LiRa [457]

Answer:

The ball travel horizontally 37 feet before it hits the ground

Step-by-step explanation:

we have

$A(x)=-0.02x^2+0.6x+5$

where

x ----> is the horizontal distance in feet

A ---> is the altitude of the ball, in feet.

we know that

When the ball hit the ground, the altitude of the ball is equal to zero

For A(x)=0

$-0.02x^2+0.6x+5=0$

solve the quadratic equation

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.02x^2+0.6x+5=0$

$a=-0.02\\b=0.6\\c=5$

substitute in the formula

$x=\frac{-0.6\pm\sqrt{0.6^{2}-4(-0.02)(5)}} {2(-0.02)}$

$x=\frac{-0.6\pm\sqrt{0.76}} {-0.04}$

$x=\frac{-0.6\pm0.87} {-0.04}$

$x=\frac{-0.6+0.87} {-0.04}=-6.75$

$x=\frac{-0.6-0.87} {-0.04}=36.75$

therefore

The ball travel horizontally 37 feet before it hits the ground

3 0

3 years ago