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geniusboy [140]
2 years ago
11

Please help 20 points

Mathematics
2 answers:
patriot [66]2 years ago
5 0

Answer:

138

Step-by-step explanation:

6*7=42

8*6=48

6*8=48

42+48+48=138

Zielflug [23.3K]2 years ago
3 0
Your awnser is 120 if I’m wrong please tell me and I’ll help you again
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Alina [70]
If you follow the order of pemdas the answer would be (-24)
4 0
3 years ago
Please need help thank you
valentinak56 [21]
Might be 1? Because it is 100 each
5 0
3 years ago
Jose asks his friends to guess the higher of two grades he received on his math tests. He gives them two hints. The difference o
tatyana61 [14]

Answer : 96

x – y = 16 --------> equation 1

1/8 x + 1/2 y = 52

x is the higher grade and y is the lower grade

We solve the first equation for y

x - y = 16

-y = 16 -x ( divide each term by -1)

y = -16 + x

Now substitute y in second equation

1/8 x + 1/2 ( -16 + x ) = 52

1/8x - 8 + 1/2 x = 52

1/8x + 1/2x - 8 = 52

Take common denominator to combine fractions

1/8x + 4/8x -8 = 52

5/8x - 8 = 52

Add 8 on both sides

5/8x = 60

Multiply both sides by 8/5

x = 96

We know x is the higher grade

96 is the higher grade of Jose’s two tests.

8 0
3 years ago
What should i know about algebra 1 before i start
Contact [7]

Answer:nothin much

Step-by-step explanation:

8 0
3 years ago
A spherical balloon is being inflated at a rate of 3 cubic inches per second. Determine the change in the rate of the radius.How
Novay_Z [31]

Answer:

The rate rate of change of radius is \frac{1}{48\pi} inches per second when the diameter is 12 inches.

The radius is changing more rapidly when the diameter is 12 inches.

Step-by-step explanation:

Consider the provided information.

A spherical balloon is being inflated at a rate of 3 cubic inches per second.

The volume of sphere is V=\frac{4}{3}\pi r^3

Differentiate the above formula with respect to time.

\frac{dV}{dt}=4\pi r^2\frac{dr}{dt}

Substitute the respective values in the above formula,

3=4\pi 6^2\frac{dr}{dt}

\frac{1}{48\pi}=\frac{dr}{dt}

The rate rate of change of radius is \frac{1}{48\pi} inches per second when the diameter is 12 inches.

When d=16

3=4\pi 8^2\frac{dr}{dt}

\frac{3}{256\pi}=\frac{dr}{dt}

Thus, the radius is changing more rapidly when the diameter is 12 inches.

5 0
3 years ago
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