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Vedmedyk [2.9K]
2 years ago
6

1. The shape shown below is dilated by a scale factor of 2.6. It is in the attachment that was included.

Mathematics
1 answer:
kondaur [170]2 years ago
7 0

Answer:

L' = 26cm

W' = 39cm

Step-by-step explanation:

a) Given the dimension of the shape;

length L = 10cm

Width W = 15cm

After dilating by a scale factor os 2.6

New length L' = 2.6(10) = 26cm

New width = W' = 2.6(15) = 39cm

Hence the length of each sides of the dilated image are 26cm and 39cm

b) The new image will be similar to the given image but of with the resulting length gotten in (a).

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Step-by-step explanation:

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For this case we need to find first the expected value given by:

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E(X^2) =\sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2)= 0^2*0.3 +1^2*0.25 +2^2*0.2 +3^2*0.12 +4^2*0.07+ 5^2*0.04 +6^2*0.02=4.97

And the variance would be given by:

Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779

And the deviation would be:

Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54

 

8 0
3 years ago
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