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Serjik [45]
3 years ago
13

Anyone know the answer??

Mathematics
2 answers:
marissa [1.9K]3 years ago
5 0
The answer should be C.

Alenkasestr [34]3 years ago
3 0
I know the GCF is 3a
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Julie's savings account has a balance of $57.85 in January. By March, her balance is 4 times as much as her January balance. Bet
sladkih [1.3K]
January . . . $57.85

March . . . . 4 times as much = 4 (57.85) = $231.40

Deposit  78.45 more . . . ($231.40 + 78.45) = <em>$309.85</em> .

Notice that "interest" is never mentioned anywhere in this problem.
In other words, it doesn't matter whether Julie's savings account is
in a bucket in the basement, a mayonnaise jar on the porch, under
her mattress, or in a bank that pays no interest.

Without interest, $309.85 is what she <em><u>does</u></em> have<em><u /></em> in November, which
is about right for savings accounts in banks these days.

What her balance <em><u>should</u></em> be in November is an entirely different subject.

3 0
3 years ago
Read 2 more answers
Divide and write in simplest form 2 3/8 divided by 1 3/4
s344n2d4d5 [400]

First, change each mixed fraction into improper

2 3/8 = 19/8

1 3/4 = 7/4

The problem will look like: (19/8)/(7/4)

To solve, flip the second fraction, and change the division sign into a multiplication sign.

(19/8)/(7/4) = (19/8) x (4/7)

Multiply across

(19/8) x (4/7) = 76/56

Simplify.

76/56 simplified = 19/14

Change to mixed fraction

19/14 = 14/14 + 5/14 = 1 5/14

1 5/14 is your answer

hope this helps

7 0
3 years ago
10
timama [110]

Answer:

25π units^2

Step-by-step explanation:

The shape is a quarter circle with radius 10 units.

area of circle = πr^2

area of a quarter circle = (1/4)π(10 units)^2

area = 25π units^2

5 0
3 years ago
The circumference of a circle is 22 meters. What is the approximate
Aleks [24]
The Diameter of the circle =7m
7 0
3 years ago
Element X decays radioactively with a half-life of eight minutes. If there are 800 g of element X, how long, to the nearest 10th
Harman [31]

Answer: 41.5 min

Step-by-step explanation:

This problem can be solved with the Radioactive Half Life Formula:  

A=A_{o}.2^{\frac{-t}{h}} (1)

Where:  

A=22 g is the final amount of the radioactive element

A_{o}=800 g is the initial amount of the radioactive element  

t is the time elapsed  

h=8 min is the half life of the radioactive element  

So, we need to substitute the given values and find t from (1):  

22 g=(800 g) 2^{\frac{-t}{8 min}} (2)  

\frac{22 g}{800 g}=2^{\frac{-t}{8 min}} (3)  

\frac{11}{400}=2^{\frac{-t}{8 min}} (4)  

Applying natural logarithm in both sides:  

ln(\frac{11}{400})=ln(2^{\frac{-t}{8 min}}) (5)  

-3.593=-\frac{t}{8 min}ln(2) (6)  

Clearing t:

t=41.46 min \approx 41.5 min This is the time elapsed

7 0
3 years ago
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