Answer: x = 3, y = 1, z = 2
<u>Step-by-step explanation:</u>
EQ 1: x - y - z = 0
EQ 3:<u> -x + 2y + z = 1 </u>
y = 1
EQ 2: 2x - 3y + 2z = 7 → 1(2x - 3y + 2z = 7) → 2x - 3y + 2z = 7
EQ 3: -x + 2y + z = 1 → -2( -x + 2y + z = 1) → <u>-2x + 4y + 2z = 2</u>
y + 4z = 9
y = 1 ⇒ 1 + 4z = 9
4z = 8
z = 2
Input y = 1 and z = 2 into one of the equations to solve for x:
EQ 1: x - y - z = 0
x - (1) - (2) = 0
x - 3 = 0
x = 3
Check:
EQ 2: 2x - 3y + 2z = 7
2(3) - 3(1) + 2(2) = 7
6 - 3 + 4 = 7
3 + 4 = 7
7 = 7 
Answer:
Step-by-step explanation:
the volume of a cylinder is given by:
and the volume of a cone is given by:
since both have the same height and radius, we can solve each equation for 
(because this quantity is the same in both figures) and then match the expressions we find:
from the cylinder's volume formula:
and from the cone's volume formula:
matching the two previous expressions:
we solve for the volume of a cone 
:
substituting the value of the cylinder's volume 
Answer:
3
Step-by-step explanation:
Answer:
(x+3)(x-3)
Step-by-step explanation:
rewrite "9" as 3^2
so it is x^2-3^2
You use the difference of squares: a^2-b^2=(a+b)(a-b)
apply it: (x+3)(x-3)
The expression would equal six because two times three is six.
