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HACTEHA [7]
1 year ago
6

The half-life of gold-195m is approximately 30.5 seconds.

Mathematics
1 answer:
SCORPION-xisa [38]1 year ago
6 0

The amount of the 12 grams sample of gold-195m having a half-life of 30.5 s that would remain after 41 s is 4.726 g

<h3>How to determine the number of half-lives </h3>
  • Half-life (t½) = 30.5 s
  • Time (t) = 41 s
  • Number of half-lives (n) =?

n = t / t½

n = 41 / 30.5

n = 82/61

<h3>How to determine the amount remaining </h3>
  • Original amount (N₀) = 12 g
  • Number of half-lives (n) = 82/61
  • Amount remaining (N) =?

N = N₀ / 2ⁿ

N = 12 / 2^(82/61)

N = 4.726 g

Learn more about half life:

brainly.com/question/26374513

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