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HACTEHA [7]
1 year ago
6

The half-life of gold-195m is approximately 30.5 seconds.

Mathematics
1 answer:
SCORPION-xisa [38]1 year ago
6 0

The amount of the 12 grams sample of gold-195m having a half-life of 30.5 s that would remain after 41 s is 4.726 g

<h3>How to determine the number of half-lives </h3>
  • Half-life (t½) = 30.5 s
  • Time (t) = 41 s
  • Number of half-lives (n) =?

n = t / t½

n = 41 / 30.5

n = 82/61

<h3>How to determine the amount remaining </h3>
  • Original amount (N₀) = 12 g
  • Number of half-lives (n) = 82/61
  • Amount remaining (N) =?

N = N₀ / 2ⁿ

N = 12 / 2^(82/61)

N = 4.726 g

Learn more about half life:

brainly.com/question/26374513

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8 0
3 years ago
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h = -16t^2 + 541? its been forever since i had to do this and frankly I'm completely lost. please if you answer this can you tea
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Use the quadratic formula which is
x = [-b +- sq root (b^2 -4*a*c)] / 2*a
x = [-0 +-sq root (0 -4*-16*541)] / 2 * -16
x = + - sq root (0 -4*-16*541) / -32
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x1 = 186.075 / -32 = <span> <span> <span> -5.81484375 </span> </span> </span>
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