Question

The half-life of gold-195m is approximately 30.5 seconds.

Answer 1

The amount of the 12 grams sample of gold-195m having a half-life of 30.5 s that would remain after 41 s is 4.726 g

How to determine the number of half-lives

• Half-life (t½) = 30.5 s
• Time (t) = 41 s

• Number of half-lives (n) =?

n = t / t½

n = 41 / 30.5

n = 82/61

How to determine the amount remaining

• Original amount (N₀) = 12 g
• Number of half-lives (n) = 82/61

• Amount remaining (N) =?

N = N₀ / 2ⁿ

N = 12 / 2^(82/61)

N = 4.726 g

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