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My name is Ann [436]
3 years ago
14

The jones family drive 200 miles in 5 hours. The grant family drives 360 miles in 6 hours. Compare the car trips. Assume they bo

th traveled at a constant rate
Mathematics
1 answer:
Oliga [24]3 years ago
6 0

In this question, we're comparing the two car trips that were give to us.

We know that the Jones family drove 200 miles in 5 hours

We also know that the Grant family drove 360 miles in 6 hours.

Lets see how many miles each family drives in 1 hour

Jones Family:

200 ÷ 5 = 40 mph

Grant Family:

360 ÷ 6 = 60 mph

We see that the Grant family travels more per hour than the Jones family.

This means that our comparison between the two car trips is that the Grant Family is going faster.

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At a college campus, random drug tests are carried out to prevent use of prohibited drugs by athletes. Of all the athletes on ca
saw5 [17]

Answer:

a) 0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

b) 0.2693 = 26.93% probability that this drug user never used the prohibited drug.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

A. If an athlete is selected at random, what is the probability that athlete will test positive for prohibited drug use?

100 - 5 = 95% of 8%

100 - 13 = 87% of 17%

11% of 75%

So

p = 0.95*0.08 + 0.87*0.17 + 0.11*0.75 = 0.3064

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

B. If an athlete tests positive after a drug test, what is the probability that this drug user never used the prohibited drug?

Conditional Probability

Event A: Tests Positive

Event B: Never used the drug.

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use

This means that P(A) = 0.3064

Probability of testing positive while never using the drug.

11% of 75%. So

P(A \cap B) = 0.11*0.75 = 0.0825

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0825}{0.3064} = 0.2693

0.2693 = 26.93% probability that this drug user never used the prohibited drug.

8 0
3 years ago
PLEASE ANSWER THIS QUESTION CORRECTLY AND I WILL MARK YOU AS THE BRAINLIEST
cluponka [151]

Answer:

2.    (x - 4)^2 = 23

Step-by-step explanation:

x^2 - 8x - 7 = 0

x^2 - 8x ~~~~~ = 7

x^2 - 8x + 16 = 7 + 16

(x - 4)^2 = 23

8 0
3 years ago
Find the difference of 13 2/5 and 3 3/4
givi [52]

Answer:

9 13/20

Step-by-step explanation:

5 0
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If f(x) = 3^x and g(x) = 3^(x+1)+6. Describe the transformations from f(x) to g(x).
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To move tot he right h units, subtract h from every x to move up k units, add k to the whole equaiton added 1 to every x (subtract -1) added6 to whole thing moved -1 to right (moved 1 to left) moved up 6 units answer is A
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Maria has a savings account. Every month she deposits $30 in it. The graph
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e owou

Step-by-step explanation: 123

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