Question

Err i dont know U>U here you go peeps

Answer 1

Answer:

${x}^{2} + {y}^{2} + 4x - 2y = - 1 \\ ( {x}^{2}+2\times2\times x + {2}^{2} ) - 4 + ({y}^{2} - 2 \times 1 \times y + {1}^{2} ) - 1 = - 1 \\ {(x + 2)}^{2} - 4 + {(y - 1)}^{2} - 1 = - 1 \\ {(x + 2)}^{2} + {(y - 1)}^{2} = 4\\ {(x + 2)}^{2} + {(y - 1)}^{2} = {( 2) }^{2}$

Therefore, the centre of the circle is in ( -2, 1 )

and the radius of the circle is 2.

Formula used :-----

${(x - a)}^{2} + {(y - b)}^{2} = {r}^{2}$

equation of the circle

where r is the radius of the circle.

(A) 2 is the right answer.