Answer:
meter
Step-by-step explanation:
We have to write first what is known from the information.
Let's say, length is L, width is W, and height is H
1. The length of the box is 2 1/2 m = 2,5 m = 5/2 m, it is 1 9/16 = 25/16 times it's width (L). So we have the equation :
L ≡ ![\frac{5}{2} = \frac{25}{16} W](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%20%3D%20%5Cfrac%7B25%7D%7B16%7D%20W)
Then we find the W. From the fraction above, we found W equals to
meter
2. What is the height of the box, if its volume is 12 3/4 m^3 = 51/4 m^3
Formula of a volume is :
The area wide times the height
In this problem, the equation is :
L × W × H = Volume
Insert the numbers,
×
× H = ![\frac{51}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B51%7D%7B4%7D)
From the fraction above, we can find that H equals to
meter
Answer:
-15
Step-by-step explanation:
-15²
= -15×-15
= 225
hope it helps!!
Answer:
x = 2
Step-by-step explanation:
Express the ratio in fractional form
=
( cross- multiply )
6x = 12 ( divide both sides by 6 )
x = 2
The correct answer is the first one(a): To get the system B,..., the first equation multiplied by 4...
Explanation:
1. Let us first multiple the first equation in System A with 4, we would get:
4(2x - y) = 4 * 3
=> 8x - 4y = 12 --- (A)
Now add the equation (A) and the second equation of System A:
8x - 4y = 12
3x + 4y = 10
------------------
11x = 22
Hence,
System B:
2x - y = 3
11x = 22
-i