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Aleksandr-060686 [28]
2 years ago
7

I GIVEE BRAINLILSTT .

Mathematics
1 answer:
bearhunter [10]2 years ago
5 0

Answer:

xcvbxc vx

Step-by-step explanation:

xcv xc c cx xc xcz xzcxcxzc

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What is the answer to 11/12×6=​
Mademuasel [1]

Answer:

\frac{11}{2}

Step-by-step explanation:

\frac{11}{12} x 6 = \frac{11}{2}

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3 years ago
PLEASE HELP FAST!!!! 40 POINTS!!!!!!
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Commutative property of addition
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The most common form of color blindness is an inability to distinguish red from green. However, this particular form of color bl
Alecsey [184]

Answer:

(a) The correct answer is P (CBM) = 0.79.

(b) The probability of selecting an American female who is not red-green color-blind is 0.996.

(c) The probability that neither are red-green color-blind is 0.9263.

(d) The probability that at least one of them is red-green color-blind is 0.0737.

Step-by-step explanation:

The variables CBM and CBW are denoted as the events that an American man or an American woman is colorblind, respectively.

It is provided that 79% of men and 0.4% of women are colorblind, i.e.

P (CBM) = 0.79

P (CBW) = 0.004

(a)

The probability of selecting an American male who is red-green color-blind is, 0.79.

Thus, the correct answer is P (CBM) = 0.79.

(b)

The probability of the complement of an event is the probability of that event not happening.

Then,

P(not CBW) = 1 - P(CBW)

                   = 1 - 0.004

                   = 0.996.

Thus, the probability of selecting an American female who is not red-green color-blind is 0.996.

(c)

The probability the woman is not colorblind is 0.996.

The probability that the man is  not color- blind is,

P(not CBM) = 1 - P(CBM)

                   = 1 - 0.004  

                   = 0.93.

The man and woman are selected independently.

Compute the probability that neither are red-green color-blind as follows:

P(\text{Neither is Colorblind}) = P(\text{not CBM}) \times  P(\text{not CBW})\\ = 0.93 \times  0.996 \\= 0.92628\\\approx 0.9263

Thus, the probability that neither are red-green color-blind is 0.9263.

(d)

It is provided that a one man and one woman are selected at random.

The event that “At least one is colorblind” is the complement of part (d) that “Neither is  Colorblind.”

Compute the probability that at least one of them is red-green color-blind as follows:

P (\text{At least one is Colorblind}) = 1 - P (\text{Neither is Colorblind})\\ = 1 - 0.9263 \\= 0.0737

Thus, the probability that at least one of them is red-green color-blind is 0.0737.

6 0
3 years ago
Aiko jumped rope for an amazing 20 minutes. She stoped at 8:05. When did she start jumping?
marissa [1.9K]
If she stopped at 8;05, and she started 20 minutes earlier, just imaging a clock at 8:05 and turn back time 20 minutes.

Five minutes would be 8:00, ten minutes is 7:55, fifteen minutes is 7:50, and twenty minutes is 7:45. This, she started at 7:45
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3 years ago
1 1/5 + 3/4 - (-3 3/5) - (-2 1/4)
babymother [125]

Step-by-step explanation:

= 1 \frac{1}{5}  +  \frac{3}{4}  - ( - 3 \frac{3}{5} ) - ( - 2 \frac{1}{4} )

= 1 \frac{1}{5}  +  \frac{3}{4}  + 3 \frac{3}{5}  + 2 \frac{1}{4}

= (1 + 3 + 2) + ( \frac{1}{5} +  \frac{3}{4} +  \frac{3}{5}   +  \frac{1}{4}  )

= 6 + ( \frac{4 + 15 + 12 + 5}{20} )

=  6 +  \frac{36}{20}

= 1 + 6 +  \frac{16}{20}

= 7 +   \frac{4}{5}

= 7 \frac{4}{5}

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3 years ago
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