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3 years ago

I WILL AWARD BRAINLIEST!!! PLEASE HELP!!! SOLVE FOR EACH!!!!

Mathematics

1 answer:

Ganezh [65]3 years ago

8 0

Answer:

1. A(3/2,6)

B(15,33)

2.A(2/9,1/3)

B(2/3,-1/3)

Step-by-step explanation:

1) y−2x=3; A(...; 6), B(15; ...)

We know y =6

Substitute this into the equation

6 -2x =3

Subtract 6 from each side

6-6 -2x=3-6

-2x = -3

Divide by -2

x = -3/-2

x = 3/2

A(3/2,6)

We know x = 15

y - 2(15) =3

y - 30 = 3

Add 30 to each side

y-30+30 = 3+30

y = 33

B(15,33)

2) 4.5x+3y=2; A(...; 1/3 ), B( 2/3 ; ...)

We know y = 1/3

4.5x + 3(1/3) = 2

4.5x +1 =2

Subtract 1 from each side

4.5x +1-1=2-1

4.5x = 1

Divide each side by 4.5

x = 1/4.5

x = 10/45

x =2/9

A(2/9,1/3)

Let x =2/3

4.5(2/3) +3y =2

3 +3y =2

Subtract 3 from each side

3-3+3y = 2-3

3y = -1

Divide by 3

y = -1/3

B(2/3,-1/3)

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Answer:

The roots (zeros) of the function are:

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Step-by-step explanation:

Given the function

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Answer:

The viewing angles are as follows:

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For x=15 feet, θ = 0.726 radians

For x=20 feet, θ = 0.691 radians

For x=25 feet, θ = 0.640 radians

Step-by-step explanation:

The viewing angle is given as:

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The question is asking us to find the viewing angle θ at various distances. The distance value needs to be substituted in the above equation in place of x. So,

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For x = 15 feet:

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For x = 20 feet:

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