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Mathematics

2 answers:

NemiM [27]3 years ago

6 0

Answer:

Slope: -4

Step-by-step explanation:

scoundrel [369]3 years ago

3 0

Answer:

Slope: − 4

y-intercept: ( 0 , 0 )

x y 0/ 0

1 /− 4

Step-by-step explanation:

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HELP ME I NEED TO FIND THE SLOPEEE!!

N76 [4]

Answer:

y=3/4 x+1

Step-by-step explanation:

first you start with y=mx+b find the y intercept first which is 1 next you just count down the block which is 3 then count to the right till you find a spot where it lands which would get you y=3/4+1

5 0

2 years ago

Read 2 more answers

The highest scorer of the women's basketball championship was Jessica Bradley. She scored 114 more points than Tina Harner, her

Harman [31]

THIS IS AN EXAMPLE:

Answer: Bradley scored 854 points and Harner scored 748 points.

Step-by-step explanation:

Start by representing the problem mathematically. "B" will represent Bradley's score, and "H" will represent Harner's score.

B+H=1602 represents that the sum of the scores is 1602.

B-H=106 represents that Bradley has 106 more points than Harner.

Now, combine the like terms in the two equations to get 2B=1708 . Now divide each side by two to find that Bradley scored 854 points.

Now, we can just subtract Bradley's score from the total score to get Harner's score. 1602-854=748, so Harner scored 748 points.

8 0

3 years ago

Read 2 more answers

Find the six trigonometric function values for angle ∅ where its adjacent side is -9 and its hypotenuse is 41. (Theta is located

arsen [322]

Check the picture below.

$\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\
-------------------------------$

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~ cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~ tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}
\\\\\\
csc(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{opposite}{40}}\qquad ~~sec(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{adjacent}{-9}}\qquad ~~cot(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{opposite}{40}}$