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3 years ago

The entire question is un the picture

Mathematics

1 answer:

irakobra [83]3 years ago

8 0

The intersection of the two equations is (1, 1/5). Since the question is asking for the value of x, x = 1.

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What is the missing length??

amid [387]

Answer

The missing length is 10

Step-by-step explanation:

Represent the missing length with x

The sides of the given shape are directly proportional.

Mathematically:

(15 + x) to (12 + 8) and x to 7

Represent as a ratio:

$(15 + x) : (12 + 8) = x : 8$

$15 + x : 20= x : 8$

Convert to fraction

$\frac{15 + x}{20} = \frac{x}{8}$

Cross Multiply:

$(15 + x)*8 = 20 * x$

$120 + 8x = 20x$

Collect Like Terms

$20x - 8x = 120$

$12x = 120$

Solve for x

$x = \frac{120}{10}$

$x = 10$

<em>The length of the missing side is 10</em>

4 0

3 years ago

Please show your work

Natasha_Volkova [10]

Answer:

X is equal to 4

5 0

3 years ago

Twenty-one boys and eight girls go on a camping trip. In how many ways can a group of six be selected to gather firewood, given

lorasvet [3.4K]

(a) there are 8C2 = 28 ways of picking 2 girls from 8
And there are 21C4 = 5985 ways of picking 4 boys

Required number of ways for 2g / 4b = 28 * 5985 = 167,580

(b) at least 2 girls means combinations of 2g/4b , 3g,3b , 4g/2b , 5g 1b or
6 girls.

2g/4b = 167,580 ways
3g/3b = 8C3 * 21C3 = 56 * 1330 = 74,480
4g/2b = 8C4* 21C2 = 70 * 210 = 14,700
5g 1b = 8C5* 21 = 56*21 = 1176
6 girls = 8C6 = 28

adding these up we get the answer to (b) which is 257,964

6 0

3 years ago

5/6 x 3/20 as a fraction

Fantom [35]

Answer:

1/8

Step-by-step explanation:

7 0

3 years ago

Estimate the perimeter and the area of the shaded figure to the nearest whole number.

soldier1979 [14.2K]

Answer:

Step-by-step explanation:

The area and perimeter of the given shaded figure are respectively 33.12 unit² and 20.56 units.

Area and perimeter-based problem:

What information do we have?

Radius of semi-circle = 8 / 2 = 4 unit

Length of remain Rectangle = 8 unit

Width of remain Rectangle = 2 unit

Perimeter of shaded figure = πr + (l + 2b)

Perimeter of shaded figure = (3.14)(4) + [4 + (2)(2)]

Perimeter of shaded figure = 12.56 + 4 + 4

Perimeter of shaded figure = 20.56 units

Area of shaded figure = πr²/2 + lb/2

Area of shaded figure = (3.14)(4)²/2 + (8)(2)/2

Area of shaded figure = (3.14)(8) + 8

Area of shaded figure = 25.12 + 8

Area of shaded figure = 33.12 unit²

5 0

2 years ago

Read 2 more answers