to find the inverse exchange the x and y and then solve for y
y =2x^2
x =2y^2
divide by 2
x/2 = y^2
take the square root of each side
sqrt(x/2) =y
the inverse of y =2x^2 is sqrt(x/2)
Answer:
C. 0 ≤ X ≤ 40
Step-by-step explanation:
The equation is valid for positive values of x not greater than 40.
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Personally, I might put the domain at 1 ≤ x ≤ 40, because there's no point in using the equation (or parking the bus) if zero people are going on the trip.
Answer:
-16(1)^2+60(1)= -16+60=44
Step-by-step explanation:
Answer:
0.25 rad to the nearest hundredth radian
Step-by-step explanation:
Here is the complete question
Suppose a projectile is fired from a cannon with velocity vo and angle of elevation (theta). The horizontal distance R(θ) it travels (in feet) is given by the following.
R(θ) = v₀²sin2θ/32
If vo=80ft/s what angel (theta) (in radians) should be used to hit a target on the ground 95 feet in front of the cannon?
Do not round any intermediate computations, and round your answer(s) to the nearest hundredth of a radian.
(θ)= ?rad
Solution
R(θ) = v₀²sin2θ/32
If v₀ = 80 ft/s and R(θ) = 95 ft
θ = [sin⁻¹(32R(θ)/v₀²)]/2
= [sin⁻¹(32 × 95/80²)]/2
= [sin⁻¹(3040/6400)]/2
= [sin⁻¹(0.475)]/2
= 28.36°/2
= 14.18°
Converting 14.18° to radians, we have 14.18° × π/180° = 0.2475 rad
= 0.25 rad to the nearest hundredth radian
Answer:
<u><em>True</em></u> because they both are triangles, they both have tree side but one is just smaller than the other.
