4^(12-4x)=256 realize that 256 is 4^4 so we really have:
4^(12-4x)=4^4 taking the natural log of both sides
(12-4x)ln4=4ln4 dividing both sides by ln4
12-4x=4 subtract 12 from both sides
-4x=-8 divide both sides by -4
x=2
Answer:
3088.1931 is your answer
Step-by-step explanation:
That's not correct. The terms 2a and 3b are not like terms, so we cannot combine them to get 5ab. We simply leave it as 2a+3b.
If you had 2a+3a, then it would simplify to 5a
Similarly, 2b+3b = 5b
Or you could have 2ab+3ab = 5ab
The key is that the variable portions must match up to be able to add them.
1,2,4 & 8
12*2<span> = 24</span>
32*2<span> = 64 </span>
44*2<span> = 88 </span>
6*4 = 24
16*4 = 24
<span>etc. </span>
-2 (x+1)= -8x+1
-2x-2= -8x+1
+2x. +2x
-2= -6x+1
-1. -1
-3= -6x
÷-6
x=.5
X=0.5
