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choli [55]
3 years ago
14

A restaurant has small tables (s) and large tables (L). Small tables seat four

Mathematics
1 answer:
xenn [34]3 years ago
5 0
Umm how many tables r their the question isn’t correct ?!
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X= ? The trainable a below are similar
ratelena [41]

\frac{x + 7}{3x + 3}  =  \frac{19}{38} \\ \Leftrightarrow  \frac{x + 7}{3x + 3}  =  \frac{1}{2}  \\ \Leftrightarrow 2x + 14 = 3x + 3 \\ \Leftrightarrow x = 11

6 0
3 years ago
Which expression shows the prime factorization of 40?
Stella [2.4K]
B. 2 time 2 is 4 , 4 times two is 8, 8 times five is 40
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3 years ago
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What is the domain of y = csc(x)?
Stells [14]

Answer:

csc

Step-by-step explanation:

7 0
3 years ago
I don’t know what the answer to this question is , help
ipn [44]

Answer:

(4, 0)

Step-by-step explanation:

given the 2 equations

y = x - 4 → (1)

- 4x - 6y = - 16 → (2)

substitute y = x - 4 into (2)

- 4x - 6(x - 4) = - 16

- 4x - 6x + 24 = - 16

- 10x + 24 = - 16 ( subtract 24 from both sides )

- 10x = - 40 ( divide both sides by - 10 )

x = 4

substitute x = 4 into (1) for corresponding value of y

y = 4 - 4 = 0

solution is (4, 0)

3 0
3 years ago
A psychological experiment was conducted to investigate the length of time (time delay) between the administration of a stimulus
aleksklad [387]

Answer:

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

The significance level for this test is 0.05.

Step-by-step explanation:

In this case, we want to prove if there is significant evidence that the mean differs from 1.6 seconds. That is the same as having evidence to reject the the hypothesis H_0:\mu= 1.6 (the null hypothesis always have the equal sign).

We have to test the null hypothesis

H_0:\mu= 1.6

The significance level for this test is 0.05

Calculation of the t-statistic:

t=\frac{M-\mu}{s/\sqrt{n}} =\frac{2.2-1.6}{0.57/\sqrt{36}} =\frac{0.6}{0.063}= 9.47

If we look up in a t-table for t=9.47 and df=(36-1)=35, we get this value appears with a probability of zero. A large number like that is very unlikely to happen.

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

6 0
3 years ago
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