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3 years ago

Write an equation of the parabola that has the same shape as the graph of f(x), but with the point (,) as the vertex.

Mathematics

1 answer:

erik [133]3 years ago

5 0

Answer:

y=3(x-9)^2+4

Step-by-step explanation:

To move a parabola horizontally to the right, subtract 9.

To move it upward 4 units, you simply have to add 4.

These do not change the characteristics of the shape. I suggest looking at a set of rules that affect how the parabola moves horizontally and vertically.

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Solve for x: −2x + 5 < 7 <br> Please Help Meh!! DO you LIKE to see people STRUGGLE?!?!

Arlecino [84]

x > -1

-2x+5 < 7

-2x<2

Now since you divide by (-1) to get positive 2,you need to flip the sign

(-2)/(-1)= 2 2/(-1)=-2

2x>-2

x > -1

To check the solution do not replace the x by -1 because it shouls be more than -1 (You can choose 0,1,2,3....)

Example choose x=3

-2x3+5<7

-6+5<7

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3 years ago

You fill a 100 mL graduated cylinder with 38.5 mL of water. What is the volume?

larisa [96]

Answer:

38.5cm³

Step-by-step explanation:

1ml = 1cm³

38.5ml = 38.5cm³

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3 years ago

the art club is selling tubo of cookies dough for a fundraiser. how much Will a student earn if he or she sells 24 tus of cookie

just olya [345]

Answer:

if each tub is $12 the student would make $288

Step-by-step explanation:

3 0

3 years ago

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5 1/6 + (7 1/3)l <60

agasfer [191]

Answer:

$l$

Step-by-step explanation:

Given the inequality

$5\dfrac{1}{6}+7\dfrac{1}{3}l$

First, convert mixed numbers to improper fractions:

$5\dfrac{1}{6}=\dfrac{5\cdot 6+1}{6}=\dfrac{31}{6}\\ \\7\dfrac{1}{3}=\dfrac{7\cdot 3+1}{3}=\dfrac{22}{3}$

Now the inequality looks like

$\dfrac{31}{6}+\dfrac{22}{3}l$

Multiply it by 6:

$\dfrac{31}{6}\cdot 6+\dfrac{22}{3}l\cdot 6$

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3 years ago

What is 4/9 closest to 0,1/2 or 1

topjm [15]

Answer:

1/2

Step-by-step explanation:

4/9 is equal to 4.444 repeating so that would be closest to 1/2

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2 years ago

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Write an equation of the parabola that has the same shape as the graph of ​f(x)​, but with the point ​(​,​) as the vertex.

Write an equation of the parabola that has the same shape as the graph of f(x), but with the point (,) as the vertex.