The answer would be 8. I got that by adding up all the numbers (64) and then dividing <span>how many numbers there are total which gave me the answer of 8.</span>
Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
Find out more on solubility at brainly.com/question/23659342.
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Sorry dont know, any thing else you need help with?
The distance between the 2 points is approximately 8.25
Answer: 16
Step-by-step explanation:
We follow BIMDAS.
So it becomes :
2+2×24/4 after the first step.
Then, 4+48/4
Then, 4+12
Which is 16
