How do I show my work for this and get the answer? Thanksss

Lizzie has 30 coins that total $4.80. All of her coins are dimes, D, and quarters, Q. Algebraically determine how many of each t

Gnom [1K]

Lizzie has 18 dimes and 12 quarters

<em><u>Solution:</u></em>

Let "d" be the number of dimes

Let "q" be the number of quarters

We know that,

value of 1 dime = $ 0.10

value of 1 quarter = $ 0.25

Given that LIzzie has 30 coins

number of dimes + number of quarters = 30

d + q = 30 ---- eqn 1

Also given that the coins total $ 4.80

number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 4.80

$d \times 0.10 + q \times 0.25 = 4.80$

0.1d + 0.25q = 4.8 ------ eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

d = 30 - q ---- eqn 3

Substitute eqn 3 in eqn 2

0.1(30 - q) + 0.25q = 4.8

3 - 0.1q + 0.25q = 4.8

0.15q = 1.8

From eqn 3,

d = 30 - 12

Thus she has 18 dimes and 12 quarters

6 0

3 years ago

[3x^(2/3)] • [7x^(1/4)]<br><br> photo of equation above

aalyn [17]

$\bf a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n}
\qquad \qquad
\sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\left( 3x^{\frac{2}{3}} \right)\left( 7x^{\frac{1}{4}} \right)\implies 3\cdot 7x^{\frac{2}{3}}\cdot x^{\frac{1}{4}}\implies 21x^{\frac{2}{3}+\frac{1}{4}}\implies 21x^{\frac{(4)2+(3)1}{12}}
\\\\\\
21x^{\frac{11}{12}}\implies 21\sqrt[12]{x^{11}}$

6 0

3 years ago

Read 2 more answers

Can the sides of a triangle have lengths 1, 8, and 9?

Svetllana [295]

Answer:

no

Step-by-step explanation:

8 0

2 years ago

Suppose we have a binomial experiment in which success is defined to be a particular quality or attribute that interests us.

mestny [16]

For a binomial experiment in which success is defined to be a particular quality or attribute that interests us, with n=36 and p as 0.23, we can approximate p hat by a normal distribution.

Since n=36 , p=0.23 , thus q= 1-p = 1-0.23=0.77

therefore,

n*p= 36*0.23 =8.28>5

n*q = 36*0.77=27.22>5

and therefore, p hat can be approximated by a normal random variable, because n*p>5 and n*q>5.

The question is incomplete, a possible complete question is:

Suppose we have a binomial experiment in which success is defined to be a particular quality or attribute that interests us.

Suppose n = 36 and p = 0.23. Can we approximate p hat by a normal distribution? Why? (Use 2 decimal places.)

n*p = ?

n*q = ?

Learn to know more about binomial experiments at

brainly.com/question/1580153

#SPJ4

3 0

1 year ago

14 (OM) Radicals and Estimation (2 pts) Without a calculator, estimate the radical and explain how you estimated. Then using a c

Irina-Kira [14]

Q) Without a calculator, we must estimate the value of the following expression:

$3-\sqrt[]{38}.$

A) I estimate 3 - √38 to be approximately -3.2.

First, we estimate the value of √38. √38 is between √36 and √49, but close to √36 (since 38 is closer to 4 than it is to 9). Since √36 is 6, √38 is probably something like 6.1 or 6.2. Filling 6.2 in the expression and simplifying, we have this:

$3-6.2=-3.2.$

So, I expect the number 3 - √38 to be close to -3.2.

Using a calculator we find that: 3 - √38 ≅ -3.16, which it is approximately the result that we found.

Answer

Without a calculator we find that 3 - √38 ≅ -3.2.

5 0

11 months ago