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shusha [124]
3 years ago
9

How many times greater is the value of the 2 digit in 20 than the 2 digit in 952?

Mathematics
1 answer:
Alex Ar [27]3 years ago
7 0
The answer is 10.......
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Write the slope- intercept form of the equation of the line through (0,3) and (1,1)
PolarNik [594]

Answer:

y = - 2x + 3

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

Calculate m using the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (1,1)

m = \frac{1-3}{1-0} = - 2

note the line passes through (0, 3) ⇒ c = 3

y = - 2x + 3 ← equation in slope-intercept form


6 0
3 years ago
Find the value of x<br> A) 22.5<br> B) 18.5<br> C) 18<br> D) 12
cluponka [151]

Answer:

A) 22.5

Step-by-step explanation:

The product of the length of one secant segment and its external part is equal to the product of the length of the other secant segment and its external part.

(5+13)*5 = x*4

18*5 = 4x

90 = 4x

Divide each side by 4

90/4 =4x/4

22.5 =x

7 0
4 years ago
What is the most reasonable estimate for the sum? 9/11 + 3/5
Eddi Din [679]
The exact answer would be 78/55, or 1 23/55
7 0
3 years ago
Read 2 more answers
A) Let X be a random variable that can assume only positive integer values, and assume its probability function is P(X -n) A/3^n
kramer

Answer:

a) The value of A = 2

b) The value of B  = \dfrac{1}{12}

Step-by-step explanation:

a)

Given that:

X should be the random variable that assumes only positive integer values.

The probability function; P[X = n] = \dfrac{A}{3^n} for some constant A and n ≥ 1.

Then, let \sum \limits ^{\infty}_{n =1} P[X =n] = 1

This implies that:

A \sum \limits ^{\infty}_{n =1} \dfrac{1}{3^n}= 1

A \times  \dfrac{\dfrac{1}{3}}{1 - \dfrac{1}{3}} = 1

A \times  \dfrac{\dfrac{1}{3}}{\dfrac{2}{3}} = 1

A \times \dfrac{1}{2}=1

A = 2

Thus, the value of A = 2

b)

Suppose X represents a e constant A (n> 1). Find A.

b) Let X be a continuous random variable that can assume values between 0 and 3

Then, the density function of x is:

f_x(x) = \left \{ {{B(x^2+1)}   \ \ \ 0 \le x \le 3  \ \ \ \atop {0} \ \ \ otherwise} \right.

where; B is constant.

Then, using the property of the probability density function:

\int ^3_0 \ B (x^2+1 ) \ dx = 1\\

Taking the integral, we have:

B \Big [\dfrac{x^3}{3} +x \Big ]^3_0 = 1

B \Big [\dfrac{3^3}{3} +3 \Big ]= 1

B \Big [\dfrac{27}{3} +3 \Big ] = 1

B [ 9 +3 ] = 1

B [ 12 ] = 1

Divide both sides by 12

B  = \dfrac{1}{12}

5 0
3 years ago
Frank works at our apartment Depot and earns $8.50 per hour. Last week he worked 36 hours. What was his total pay?
prohojiy [21]

360 dollars last week

8 0
4 years ago
Read 2 more answers
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