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katen-ka-za [31]
3 years ago
15

Escribe un trinomio utilizando una variable de grado cinco en forma estandar.

Mathematics
1 answer:
Gelneren [198K]3 years ago
4 0

Answer:

Step-by-step explanation:Un polinomio de una variable viene dado por la siguiente expresión: -

donde A, B, C, D, E son los coeficientes de los términos en el polinomio y x es la variable de la ecuación.

A es el coeficiente principal y no puede ser cero, es decir, A ≠ 0.

n es el grado del polinomio.

Dice escribir un trinomio en una variable de grado 5.

Trinomio significa solo tres términos con coeficientes distintos de cero, y el grado 5 significa n = 5.

Podría haber muchas respuestas, pero un ejemplo de "trinomio de grado 5" sería: -

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Susan started her homework at 1{:}59\text { p.M.}1:59 p.M.1, colon, 59, start text, space, p, point, m, point, end text and fini
inn [45]

Answer:

Step-by-step explanation:

Susan started her homework at = 1:59 pm

She took time = 96 mins

Time at which she had volleyball practice = 4:00 pm

So, time between her starting of homework and starting of volleyball is given by

1:59 pm to 4:00 pm = 2 hrs and 1 mins

2 hr 1 min = 120 mins + 1 min = 121 mins

But she took 96 mins to do her homework, so

Out of 121 mins, 96 mins she took for homework

Remaining time = 121 mins - 96 mins = 25 mins

Therefore, time Susan had between finishing her homework and the beginning of volleyball practice is 25 mins

7 0
4 years ago
Prove that the roots of x2+(1-k)x+k-3=0 are real for all real values of k​
masha68 [24]

Answer:

Roots are not real

Step-by-step explanation:

To prove : The roots of x^2 +(1-k)x+k-3=0x

2

+(1−k)x+k−3=0 are real for all real values of k ?

Solution :

The roots are real when discriminant is greater than equal to zero.

i.e. b^2-4ac\geq 0b

2

−4ac≥0

The quadratic equation x^2 +(1-k)x+k-3=0x

2

+(1−k)x+k−3=0

Here, a=1, b=1-k and c=k-3

Substitute the values,

We find the discriminant,

D=(1-k)^2-4(1)(k-3)D=(1−k)

2

−4(1)(k−3)

D=1+k^2-2k-4k+12D=1+k

2

−2k−4k+12

D=k^2-6k+13D=k

2

−6k+13

D=(k-(3+2i))(k+(3+2i))D=(k−(3+2i))(k+(3+2i))

For roots to be real, D ≥ 0

But the roots are imaginary therefore the roots of the given equation are not real for any value of k.

6 0
3 years ago
What is the value of x in the figure below (PLS HELP ILL GIVE YOU 100 POINTS AND MARK BRAINLIEST) ​
Andreyy89
B / 24 because I had to do this whole assignment . I got 100 on it . Non of the others make since if u do the math
5 0
3 years ago
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Dalia bought a few swirl marbles and divided it equally among four of her friends
Gennadij [26K]

Answer:

16 ang answer

Step-by-step explanation:

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I am pretty sure that it is the first choice because it is the only one that is true

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